Chapter 5: Problem 2
The product obtained in the following reaction is
(A)
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 5: Problem 2
The product obtained in the following reaction is
(A)
These are the key concepts you need to understand to accurately answer the question.
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Get started for freePhenylglyoxal, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCHO}\), on heating with concentrated sodium hydroxide yields (A) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COONa}\) and \(\mathrm{CH}_{3} \mathrm{OH}\) (B) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHOHCOONa}\) (C) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}\) and \(\mathrm{HCOONa}\) (D) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COONa}\) and \(\mathrm{HCOONa}\)
[n the following reaction, final mixture contains:
The product category obtained in Aldol reaction is (A) \(\alpha\)-Hydroxy Carbonyl (B) \(\beta\)-Hydroxy Ester (C) \(\beta\)-Hydroxy Carbonyl (D) \(\alpha\)-Hydroxy Ester
Choose the correct option(s) about reaction sequence :
$$
\mathrm{L}_{\mathrm{O}}^{0}
\frac{\mathrm{m}-\mathrm{CPBA}}{\longrightarrow}(\mathrm{P})
\stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow}(\mathrm{Q})
\stackrel{\Delta}{\longrightarrow}(\mathrm{R})
$$
(A) Formation of (P) involves migration at deficient oxygen (B) (Q) has common
name succinic acid
(C) Product \((R)\) is
Consider the following sequence of reactions. The final product (Q) is : $$ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}+\mathrm{CH}_{3} \mathrm{CHO} \frac{\mathrm{NaOH}}{\mathrm{Nent}}(\mathrm{P}) \frac{(\mathrm{i}) \mathrm{L} \mathrm{L} \mathrm{HH}_{4}}{\text { (ii) } \mathrm{H}_{2} \mathrm{O}} \text { (Q) } $$ (A) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHCHOHCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (B) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (C) \(\mathrm{C} \cdot \mathrm{H}_{2} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{OH}\) (D) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO}\)
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