Question

Double bond equivalent and total number of different functional group in given compound is respectively (A) 5,6 (B) 6,7 (C) 9,8 (D) 9,7

Short answer

Based on the analysis and given options, it is not possible to provide a specific short answer without knowing the compound structure. In general, use the formula, DBE = \(\frac {C - (H + X + N)}{2} + 1\), to calculate double bond equivalents (DBEs) and identify atoms that are part of functional groups to count the number of functional groups in the compound. Compare the calculated values with the given options to find the correct answer.

Step-by-step solution

Identify the given compound

In the exercise, the specific compound is not specified. We must create a strategy that works without knowing the compound. We will, therefore, derive a formula to determine the DBE and find a method for counting functional groups.

Derive the formula to calculate Double Bond Equivalents (DBEs)

We can calculate the DBE using the following formula: DBE = \(\frac {C - (H + X + N)}{2} + 1\) Where C is the number of carbons, H is the number of hydrogens, X is the number of halogens, and N is the number of nitrogens in the compound.

Count the number of functional groups in the compound.

To identify the functional groups present in the compound, we can count the number of atoms that are not part of a C-C single bond or an alkane. These atoms are typically part of the functional groups that give the compound its unique chemical properties.

Apply the DBE formula and identify functional groups

Since we do not have a specific compound given in this problem, we must apply our strategy in a way that solves the problem for any given compound: 1. Calculate the DBE using the formula in Step 2. 2. Count the number of functional groups in the compound.

Compare the calculated values with given options

Compare the calculated DBE and the number of functional groups to the given options, (A), (B), (C), and (D), to find the correct answer. Once you have calculated the DBE and identified the number of functional groups for a given compound using the above steps, you can confidently select the correct answer among the given options.

Key concepts

Functional Groups

Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. Understanding these groups is fundamental in organic chemistry because they determine the properties and reactivity of organic compounds. Each functional group behaves somewhat independently from the rest of the molecule, and their properties and reactions are well-known, allowing chemists to predict the behavior of new compounds when these groups are present.

Functional groups include, but are not limited to:

• Alcohols (-OH)
• Aldehydes (-CHO)
• Ketones (C=O)
• Carboxylic Acids (-COOH)
• Amides (-CONH)
• Esters (RCOOR)

They can significantly modify a compound's solubility, acidity, and boiling and melting points. For example, the hydroxyl group (-OH) can increase a compound's polarity, making it more soluble in water. Recognizing and quantifying these functional groups is key in solving questions related to the chemical structure and properties in various exams, including JEE.

Organic Chemistry

Organic chemistry is the branch of chemistry concerned with the structure, properties, and reactions of organic compounds and organic materials, which contain carbon atoms. Carbon's ability to form bonds with itself and other elements, such as hydrogen, nitrogen, oxygen, and halogens, creates an immense variety of chemical structures.

In organic chemistry, understanding the concept of Double Bond Equivalents (DBE) is crucial. DBE is a calculation used to infer the number of pi bonds and rings in a molecule. It helps in developing a preliminary idea about the possible structure of a compound. The formula for DBE is:\[ DBE = \frac{C - (H + X + N)}{2} + 1 \]where:

• \(C\) is the number of carbons
• \(H\) is the number of hydrogens
• \(X\) is the number of halogens
• \(N\) is the number of nitrogens

This calculation is one of the numerous tools that chemists rely on to decipher the structure and reactivity of organic molecules, which is paramount in both theoretical study and practical applications.

JEE Exam Preparation

When preparing for competitive exams like the JEE (Joint Entrance Examination), it is important to focus on a deep understanding of the fundamental concepts of organic chemistry, such as functional groups and the double bond equivalent. These concepts are frequently tested as they are significant in understanding the composition and reactions of organic molecules.

To excel in JEE organic chemistry, here are some study tips:

• Understand and memorize the key functional groups and their general reactions.
• Practice calculating the Double Bond Equivalent (DBE) for various molecules to become familiar with quickly deciphering molecule structures.
• Utilize resources like textbooks, online tutorials, and past exam papers to get accustomed to the format and types of questions asked.
• Regular revision and practice through problem-solving can greatly enhance your ability to recall important reactions and mechanisms during the exam.

By strengthening these core areas, you can improve your problem-solving speed and accuracy, which are crucial for achieving top scores in the exam.