Question

The IUPAC name of the following compound is COC(=O)CC(=O)OC(=O)CC(=O)OC (A) methoxy carbonyl methanoic anhydride (B) ethoxy carbonyl ethanoic anhydride (C) methyl carbonyl ethanoate (D) methoxy carbonyl ethanoic anhydride

Short answer

(D) Methoxy carbonyl ethanoic anhydride

Step-by-step solution

Convert SMILES notation to molecular structure

The given SMILES notation is "COC(=O)CC(=O)OC(=O)CC(=O)OC." We need to draw the molecular structure based on this notation.

Identify functional groups and the main chain

From the molecular structure, we can see that there are several functional groups and a main carbon chain. The functional groups are: 1. 4 carboxyl groups (COOH) which are reduced to anhydrides during esterification 2. 2 methoxy groups (OCH3) The main chain consists of 2 carbon atoms, making it an ethanoic backbone.

Determine and apply IUPAC naming conventions

Based on the functional groups and the main carbon chain, we can start naming the compound. 1. The main chain is an ethanoic backbone, so the base name will include "ethanoic." 2. There are 2 methoxy (OCH3) groups, which should be named as "methoxy." 3. 4 carboxyl groups (COOH) have been reduced to anhydrides, so the compound has 2 anhydride groups, as these reductions undergo esterification. Thus, we can name them "carbonyl ethanoic anhydride."

Combine all parts of the name

Combining all parts of the name, we have: "Methoxy carbonyl ethanoic anhydride"

Choose the correct answer

Based on our analysis, the correct IUPAC name for the given compound is (D) Methoxy carbonyl ethanoic anhydride.