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The compound that does not liberate \(\mathrm{CO}_{2}\) on treatment with aqueous sodium bicarbonate solution is (A) Benzoic acid (B) Benzenesulphonic acid (C) Salicylic acid (D) Carbolic acid (phenol)

Short Answer

Expert verified
The compound that does not liberate CO2 on treatment with aqueous sodium bicarbonate solution is (D) Carbolic acid (phenol). This is because phenols are weaker acids compared to the other given compounds and do not react with sodium bicarbonate under the same conditions.

Step by step solution

01

Identify the given compounds and their chemical structures

First, let's list down the given compounds and their chemical structures/formulas: (A) Benzoic acid: \(C_7H_6O_2\) (B) Benzenesulphonic acid: \(C_6H_5SO_3H\) (C) Salicylic acid: \(C_7H_6O_3\) (D) Carbolic acid (phenol): \(C_6H_5OH\)
02

Understand the reaction of acids with aqueous sodium bicarbonate

Aqueous sodium bicarbonate (\(NaHCO_3\)) reacts with acidic substances and liberates CO2 gas. Generally, compounds with an acidic hydrogen atom can generate carbon dioxide gas with sodium bicarbonate by the following generic reaction: Acid + \(NaHCO_3\) -> Salt + CO2 + H2O Now, let's analyze the given compound's reaction with sodium bicarbonate to determine which does not produce CO2 gas.
03

Analyze the reactions of the given compounds with sodium bicarbonate

(A) Benzoic acid (carboxylic acid) reacts with sodium bicarbonate to produce benzoate salt, CO2, and water as shown: \(C_7H_6O_2\) + \(NaHCO_3\) -> \(C_7H_5O_2Na\) + CO2 + H2O (B) Benzenesulphonic acid (sulfonic acid) reacts with sodium bicarbonate to produce the benzenesulfonate salt, CO2, and water as shown: \(C_6H_5SO_3H\) + \(NaHCO_3\) -> \(C_6H_5SO_3Na\) + CO2 + H2O (C) Salicylic acid (carboxylic acid) reacts with sodium bicarbonate to produce salicylate salt, CO2, and water as shown: \(C_7H_6O_3\) + \(NaHCO_3\) -> \(C_7H_5O_3Na\) + CO2 + H2O (D) Carbolic acid (phenol) has only acidic hydrogen atoms on its hydroxyl group; however, the acidity is weaker than that of the other given compounds (carboxylic and sulfonic acids). Thus, it will not react with sodium bicarbonate to produce CO2 gas, as the reaction conditions are not sufficient for the reaction to proceed. Phenols do not react with sodium bicarbonate under the same conditions as carboxylic and sulfonic acids as they are weaker acids.
04

Answer the question

Since only Carbolic acid (phenol) does not liberate CO2 gas on treatment with aqueous sodium bicarbonate solution, the correct answer is: (D) Carbolic acid (phenol)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Organic Chemistry
Organic chemistry is a branch of chemistry that deals with carbon-containing compounds. These compounds often involve carbon atoms bonded to hydrogen, oxygen, nitrogen, and other elements.
Organic molecules can vary widely, from simple structures like methane ( CH₄ ) to complex structures such as proteins and DNA.
  • Carbon's ability to form stable bonds with other elements allows for diverse chemical structures.
  • This diversity leads to vast possibilities in the behavior and reactivity of organic compounds.
  • Organic reactions often involve functional groups, like alcohols, acids, and amines.
Understanding these reactions helps us predict how compounds will interact, crucial for fields like pharmaceuticals, agriculture, and materials science.
Carboxylic Acids
Carboxylic acids are a group of organic acids that contain a carboxyl group ( -COOH ). They are known for their acidic properties, attributed to their ability to donate a proton ( H⁺ ).
  • The carboxyl group consists of a carbonyl group ( C=O ) and a hydroxyl group ( -OH ).
  • These acids are generally weak acids, but stronger than phenols and alcohols.
  • Common examples include acetic acid (vinegar) and benzoic acid, both reacting vigorously with sodium bicarbonate to release carbon dioxide.
Carboxylic acids' acidity is strong enough to allow them to react with bases like sodium bicarbonate, an important property in differentiating them from weaker acids, such as phenols.
Sulfonic Acids
Sulfonic acids are another group of strong organic acids. They contain the sulfonic group ( -SO₃H ), where the sulfur atom is bonded to three oxygen atoms, one of which has a double bond.
  • Sulfonic acids are stronger than carboxylic acids, due to greater resonance stabilization of the sulfonate ion.
  • They are highly reactive and form salts during reactions with bases.
  • Benzenesulphonic acid is a common example, reacting with sodium bicarbonate to liberate CO₂ gas.
Their strong acidic nature makes them suitable as catalysts and detergents, as well as for use in various cleaning agents.
Phenols
Phenols are a type of organic compound characterized by a hydroxyl group ( -OH ) bonded directly to an aromatic hydrocarbon group, like benzene.
  • Phenols are less acidic than carboxylic and sulfonic acids because the phenoxide ion is less stable.
  • This lower acidity results in phenols not reacting with sodium bicarbonate to produce CO₂ under normal conditions.
  • Carbolic acid, a common name for phenol, illustrates this weak acidity.
The unique structure of phenols gives them special properties, such as antiseptic qualities, making them valuable in both industrial and medical applications.
Sodium Bicarbonate
Sodium bicarbonate ( NaHCO₃ ), commonly known as baking soda, is a versatile compound with various applications in both household and industrial settings.
  • It acts as a mild base, reacting with acids to produce carbon dioxide gas, salt, and water.
  • This reaction is visible in baking, where it helps dough rise.
  • Its reactivity with carboxylic and sulfonic acids but not phenols is a key property used in chemical analysis.
In organic chemistry, sodium bicarbonate serves as a tool to test the acidity of compounds, offering insights into their chemical nature and behavior.

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Most popular questions from this chapter

The given order is not a correct for their: $$ \mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}>\mathrm{CH}_{2}=\mathrm{CH}_{2} $$ (A) Heat of hydrogenation (B) Bond length of \(\mathrm{C}=\mathrm{C}\) bond (C) Heat of hydrogenation per mole of \(\mathrm{H}_{2}\) (D) Heat of combustion

The correct order of acidic strength is/are (A) (B) (C) \(\mathrm{CH}_{3}-\mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{EtOH}>\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}>\mathrm{R}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}>\mathrm{NH}_{3}\) (D) \(\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}>\mathrm{HF}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}>\mathrm{CH}_{4}\)

\(p K_{a}\) of which compound is very close to \(p K_{a}\) of Butanoic acid?

The basic strength order of following in \(\mathrm{H}_{2} \mathrm{O}\) is (I) \(\mathrm{MeNH}_{2}\) (II) \(\mathrm{Me}_{2} \mathrm{NH}\) (III) \(\mathrm{Me}_{3} \mathrm{~N}\) (IV) \(\mathrm{Me}_{4} \mathrm{NOH}\) (A) \(\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}\) (B) \(\mathrm{IV}>\mathrm{III}>\mathrm{II}>\mathrm{I}\) (C) II > IV > I \(>\) III (D) IV > II > I > III

Choose the correct option(s). (A) As the more hyperconjugating structures form in alkene, bond length of double bond decrease. (B) Isotopic effect is observed in hyperconjugation. (C) \(\mathrm{H}_{3} \mathrm{C}^{\oplus} \mathrm{CH}_{3}\) has 9 hyperconjugation structures involving only \(\mathrm{C}-\mathrm{H}\) bond. (D) Unidirectional hyperconjugation increases stability of isobutene compared to trans-but-2-ene.

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