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Given the following two reactions and corresponding enthalpy changes,

CO(g)+SiO2(s)SiO(g)+CO2(g),ΔH=+520.9kJ8CO2(g)+Si3N4(s)3SiO2(s)+2N2O(g)+8CO(g),ΔH=+461.05kJ

Compute ΔHof the reaction5CO2(g)+Si3N4(s)3SiO(g)+2N2O(g)+5CO(g) ?

Short Answer

Expert verified

The heat change of the reaction, ΔH=2023.75kJ.

Step by step solution

01

Given data

The following reaction is given,

CO(g)+SiO2(s)SiO(g)+CO2(g),ΔH=+520.9kJ8CO2(g)+Si3N4(s)3SiO2(s)+2N2O(g)+8CO(g),ΔH=+461.05kJ

02

Concept of the thermochemistry

The study of chemical reactions and energy changes brought on by heat is known as thermochemistry.

03

Simplify the reaction

To combine the two given reactions in a way that their sum is the needed reaction.

1.CO(g)+SiO2(g)SiO(g)+CO2(g)2.8CO2(g)+Si3N4(g)3SiO2(g)+2N2O(g)+8C

Let's start by multiplying the equation (1) reaction by (3) .

1.CO(g)+SiO2(g)SiO(g)+CO2(g)/×32.8CO2(g)+Si3N4(g)3SiO2(g)+2N2O(g)+8CO(g)1.3CO(g)+3SiO2(g)3SiO(g)+3CO2(g)2.8CO2(g)+Si3N4(g)3SiO2(g)+2N2O(g)+8CO(g)

04

Add equations 1 and 2

As it can be seen by sum up these reactions get the needed reaction:

1.3CO(g)+3SiO2(g)3SiO(g)+3CO2(g)+2.8CO2(g)+Si3N4(g)3SiO2(g)+2N2O(g)+8CO(g)______________________________________________________________________________5CO2(g)+Si3N4(g)3SiO(g)+2N2O(g)+5CO(g)
05

 Step 5: Calculate change of heat

The enthalpy of this reaction is a combination of the 2 enthalpies.

The same combination is used to get the reaction:

ΔH=3×ΔH1+ΔH2ΔH=3×520.9+461.05ΔH=2023.75kJ

Therefore, the heat change of the reaction, ΔH=2023.75kJ.

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