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A process at constantandcan be described as spontaneous ifand nonspontaneous if. Over what range of temperatures is each of the following processes spontaneous? Assume that all gases are at a pressure of 1 atm. (Hint: Use Appendix D to calculateand[assumed independent of temperature and equal toand, respectively], and then use the definition of.)

(a) The rusting of iron, a complex reaction that can be approximated as

(b) The preparation offrom, a step in the manufacture of sulfuric acid:

(c) The production of the anaesthetic dinitrogen oxide through the decomposition of ammonium nitrate:

Short Answer

Expert verified

(a)

b)

c) reaction will be spontaneous at all temperatures because is negative and is positive

Step by step solution

01

 Step 1: Given data

The reaction are given:

(a)

(b)

02

Concept of the spontaneous process

A spontaneous process happens when no substance or electrical energy is introduced into the system. An increase in entropy characterizes a spontaneous process in a perfectly isolated system.

03

 Step 3: Determination of standard enthalpy change

Standard enthalpy change is shown below:

…. (i)

where, change in enthalpy of Products and Reactants

Standard entropy change

…...(ii)

where, is change in entropy of Products and Reactants

Special temperature can be calculated as follows:

If both and are negative, the reaction will be spontaneous at temperature less than , and If is negative and is positive, then the reaction will be spontaneous at all temperature

04

Step 4: (a)Calculation of enthalpy change and entropy change.

05

Step 4: Calculate of specific temperature 

T*=-1648.4kJ-549.41JK-1=-1648.4×103J-549.41JK-1=3000KThe value of temperature can be determined as follows:

The process will be spontaneous at temperature

06

Step 5 (b)Calculate of change of enthalpy and entropy

07

Step 5 (c)Calculate of change of enthalpy and entropy 

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Most popular questions from this chapter

At 12000C, the reduction of iron oxide to elemental iron and oxygen is not spontaneous:

2Fe2O3(s)4Fe(s)+3O2(g)ΔG=+840kJ

Show how this process can be made to proceed if all the oxygen generated reacts with carbon:

C(s)+O2(g)CO2(g)ΔG=-400kJ

This observation is the basis for the smelting of iron ore with coke to extract metallic iron.

(a) Use data from Appendix D to calculate H°andS°at25°Cfor the reaction

2CuCl2(s)2CuCl(s)+Cl2(g)

(b)Calculate atG°590K, assumingH°andS°are independent of temperature.

(c) Careful high-temperature measurements show that when this reaction is performed at590K,H590°is158.36kJandS°590is177.74JK-1. Use these facts to compute an improved value ofG°590for this reaction. Determine the percentage error inG°590that comes from using the298Kvalues in place of590-Kvalues in this case.

When a gas undergoes a reversible adiabatic expansion, its entropy remains constant even though the volume increases. Explain how this can be consistent with the microscopic interpretation of entropy developed in Section 13.2. (Hint: Consider what happens to the distribution of velocities in the gas.)

Question: Calculate the entropy change that results from mixing 54.0g water at273K with 27.0gwater at373K in a vessel whose walls are perfectly insulated from the surroundings. Consider the specific heat of water to be constant over the temperature range from 273 to 373Kand to have the value 4.18JK1g1.

Question: (a) Why is the entropy change of the system negative for the reaction in Problem 25, when the ions become dispersed through a large volume of solution? (Hint: Think about the role of the solvent, water.)

(b) Use Appendix D to calculate for the corresponding dissolution ofCaF2(s) . Explain why this value is even more negative than that given in Problem 25 .

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