Question

From (III) sulphate , $\mathit{F}{\mathit{e}}_{\mathbf{2}}{\left(S{O}_4\right)}_{\mathbf{3}}$is a yellow compound that is used as a coagulant in water treatment. Write a balanced chemical equation and solubility product expression for its dissolution in water.

Short answer

Coagulant and solubility product079113-16-16.1-3P

Coagulant is a substance that comes another liquid to accommodate in one place or to evaluate.

$F{e}_2{\left(S{O}_4\right)}_3\begin{array}{c}AB\leftrightarrows A^{+}+B^{-}\\ K_{SP}=\left[A^{+}\right]X{\left[B^{-}\right]}^{\text{'}}\end{array}$

Step-by-step solution

Step-1: [Another of the above question]

Given:- The name of the compound is Iron. Sulphate, Fe₂(SO₄)₃ . The balanced chemical equation is-

$F{e}_2{\left(S{O}_4\right)}_3\leftrightarrows 2F{e}^{3+}+3S{O}_4^{2-}\left(aq\right)$

The solubility product (Ksp) for the above balanced equation is:

$K_{SP}={\left[F{e}^{3+}\right]}^{2}X{\left[S{O}_4^{2-}\right]}^{3-}$

Step-2: Dissociation reaction and solubility product

Balancing the dissociation reaction of Fe₂(SO₄)₃ .

$F{e}_2{\left(S{O}_4\right)}_3\left(s\right)\leftrightarrows 2F{e}^{3+}\left(aq\right)+3S{O}_4^{2-}\left(aq\right)$

The solubility product means the total concentration of the solutes.

$K_{SP}=\left[F{e}^{2+}\right]X{\left[S{O}_4^{2-}\right]}^3$

Step-3: Conclusion

Where K_SP represents the solubility product of a reversible reaction.