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The two solids CuBr(s)) and AgBr(s) are only very slightly soluble in water: KspCuBr=4.2×10-8 andKspAgBr=7.7×10-12 . SomeCuBrs and AgBrsare both mixed into a quantity of water that is then stirred until it is saturated with respect to both solutes. Next, a small amount of KBris added and dissolves completely. Compute the ratio ofCu+ to Ag+after the system re-establishes equilibrium.

Short Answer

Expert verified

The ratio of Ag-andCu+ is2.3×102

Step by step solution

01

Reaction.

It’s given that:

AgBr(s)Ag+(aq) + Br-(aq)

Ksp= [Ag+][Br-]

KspAgBr=7.7×10-13

As we know that this two are solid so,

[Ag-]=s[Br-]=s

Let’s find the value of :

Ag-Br-=S×S=7.7×10-13S2=7.7×10-13S=8.8×10-7Ag-=8.8×10-7M

Now by mixing this two solution we get:

CuBr(s)Cu+(aq) + Br-(aq)

Ksp= [Cu+][Br-]

Ksp(CuBr)=4.2×10-8

02

Finding value for Cu and Br.

[Cu+]=S[Br-]=s

Cu+Br-=s×s=4.2×10-8S2=4.2×10-8S=2.0×10-4Cu+=4.2×10-4M

Now computing the ratio of Ag-andCu+we will get

Cu+Ag-=2.0×10-4M8.8×10-7M=2.3×102

Therefore,TheratioofAg-andCu+is2.3×102.

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