Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

One way in which photosynthetic bacteria store chemical energy is through the conversion of a compound called adenosine diphosphate (ADP), together with hydrogen phosphate ion, to adenosine triphosphate (ATP):

ADP3-+HPO42-+H3O+ATP4-+2H2OG=+34.5KJ(pH=7)

Suppose some chlorophyll molecules absorb 1.00 mol of photons of blue light with wavelength 430nm. If all this energy could be used to convert ADP to ATP at room conditions and pH 7, how many molecules of ATP would be produced per photon absorbed? (The actual number is smaller because the conversion is not 100% efficient.)

Short Answer

Expert verified

The total number of molecules of ATP produced will be 8NA.

Step by step solution

01

Definition of photoelectric effect

When light shines on a metal, the photoelectric effect results in the “expulsion of electrons” from the metal's surface termed as photoelectrons. This complete process is also known as photoemission.

02

Calculation of total energy

Given that, wavelength (λ) is 430nm at room temperature and under neutral pH.

According to photoelectric equation,

E=hcλNA

Where, h = Planck’s constant, c = speed of light, and NA= Avogadro’s number.

The known values are substituted.

E=hcλNAE=6.63×10-34×3×108430×10-9×6.023×1023E=278.598kJmol-1

03

Calculation of total number of ATP molecules

According to given information, for formation of one molecule of ATP 34.5kJ energy is required.

So, number of molecules formed due to 1 mol of photons can be given by-

n=EΔGNA

Where,

  • n is number of molecules
  • E is energy of 1 mole of photons
  • ΔG is energy of formation of one mole of ATP

Then,

n=278.59834.5NAn=8.07n8NA

Hence, 8NA of ATP can be formed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One isomer of retinal is converted to a second isomer by the absorption of a photon:

This process is a key step in the chemistry of vision. Although free retinal (in the form shown to the left of the arrow) has an absorption maximum at 376 nm, in the ultraviolet region of the spectrum this absorption shifts into the visible range when the retinal is bound in a protein, as it is in the eye.

(a) How many of the C=Cbonds are cis and how many are trans in each of the preceding structures? (When assigning labels, consider the relative positions of the two largest groups attached at each double bond.) Describe the motion that takes place upon absorption of a photon.

(b) If the ring and the−CHOgroup in retinal were replaced by−CH3groups,would the absorption maximum in the molecule shift to longer or shorter wavelengths?

Four consecutive absorption lines in the pure rotational spectrum of gaseous 1H35Clare found to have the frequencies2.50×1012,3.12×1012,3.74×1012,and4.37×1012s-1. Calculate:

  1. The moment of inertia Iof HCl(in kgm2)
  2. The energies of the J=1,J=2,andJ=3 rotational levels ofHCl, measured from theJ=0 state (in joules)
  3. The HClbond length (in angstroms)
  4. The initial and final J states for the observed absorptionlines

The vibration frequency for H2is 4400cm-1 and the energy difference between its two lowest rotational energy levels is 121.7cm-1,J=0 and .Calculate the relative populations of the v=1and v=0vibration energy levels and the relative populations of the lowest rotational energy levels for H2at the operating temperature of the space shuttle’s combustion chamber, which is 3300°C. Comment on your results.

Recall that nuclear spin states in nuclear magnetic resonance are typically separated by energies of 2 × 10-5 kJ mol-1 to 2 × 10-4 kJ mol-1 . What are the ratios of occupation probability between a pair of such levels at thermal equilibrium and a temperature of 25°C?

If laser exciting the OH radical to the v'=1level of the Ă state as described in the prior problem, what energy of photon would be emitted if the final vibration state of the OH in the ground electronic state were v''=3?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free