Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Many bleaches, including chlorine and its oxides, oxidize dye compounds in cloth. Predict which of the following will be the strongest bleach at a given concentration andpH0:NaClO3(aq),NaClO(aq),Cl2(aq) .How does the strongest chlorine-containing bleach compare in strength with ozone O3(g)?

Short Answer

Expert verified

The ozone molecule has the highest positive reduction potential, followed by the others, with an usual reduction potential of The ozone molecule is a powerful two-electron oxidant with a typical reduction potential of 2.07V.

Step by step solution

01

Definition of oxidizing agent.

Oxidizing agent: In a chemical reaction, oxidising agents are molecules that gain electrons.

02

Explanation of solution.

The positive reduction potential of a good oxidising is higher. Let's make a list of standard reduction potentials for the following compounds:

ClO_3--(aq)+6H3O++5e-12Cl2(g)+9H2O(l)Eo=1.47VClO--(aq)+2H3O++e-12Cl2(g)+3H2O(l)Eo=1.611VCl_2-(g)+2e-2Cl-(aq)Eo=1.3583V

As, has the highest positive reduction potential, and the others are listed in the following orderNaClO<NaClO_3<Cl2:

As a result,NaClO is the most powerful oxidising agent. With a typical reduction potential of 2.07V, the ozone molecule is a powerful two-electron oxidant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Overcharging a lead-acid storage battery can generate hydrogen. Write a balanced equation to represent the reaction taking place.

Question: The chief chemist of the Brite-Metal Electroplating Co. is required to certify that the rinse solutions that are discharged from the company's tin-plating process into the municipal sewer system contain no more than(parts per million) by mass ofSn2+. The chemist devises the following analytical procedure to determine the concentration. At regular intervals, a 100-mL(100-g)sample is withdrawn from the waste stream and acidified to pH=1.0. A starch solution andofpotassium iodide are added, and a current is passed through the solution between platinum electrodes. Iodine appears as a product of electrolysis at the anode when the oxidation ofSn2+toSn4+is practically complete and signals its presence with the deep blue colour of a complex formed with starch. What is the maximum duration of electrolysis to the appearance of the blue color that ensures that the concentration ofSn2+does not exceed 10 ppm?

An acidic solution containing copper ions is electrolyzed, producing gaseous oxygen (from water) at the anode and copper at the cathode. For every 16.0 g of oxygen generated 63.5 g of copper plates out. What is the oxidation state of the copper in the solution?

Question-98: A potential difference of 2.0V is impressed across a pair of inert electrodes (e.g., Platinum) that are immersed in a 0.05M aqueous KBr solution. What are the products that form at the anode and the cathode?

A galvanic cell is constructed in which a Br2|Br+half-cell is connected to aCo2+|Cohalf-cell.

(a) By referring to Appendix E, write balanced chemical equations for the half-reactions at the anode and the cathode and for the overall cell reaction.

(b) Calculate the cell potential, assuming that all reactants and products are in their standard states.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free