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Diagram the following galvanic cell, indicating the direction of flow of electrons in the external circuit and the motion of ions in the salt bridge.

Pt(s)|Cr2+(aq),Cr3+(aq)||Cu2+(aq)|Cu(s)

Write a balanced equation for the overall reaction in this cell.

Short Answer

Expert verified

Balanced equation for the overall reaction in given galvanic cell is,

2Cr2+aq+Cu2+s2Cr3+aq+Cus

Step by step solution

01

Introduction to electrochemical reactions

Electrochemical reactions are made up of two half-reactions, the anode electrode and the cathode electrode, which are combined to form the entire cell reaction.

The anode is the electrode where electrons are lost due to oxidation and the cathode is where electrons are acquired due to reduction.

02

Understanding given parameters

In the galvanic cell electrons flow from left electrode to right as Cr(II) is oxidized to Cr(III). In the salt bridge positive ions flow from left to right and negative ions flow from right to left.

03

Balancing equation for overall reaction

Anode half-reaction can be written as,

Cr2+aqCr3+aq+e-/2

Multiply by 2 on both sides of equation to satisfy the number of electrons,

2Cr2+aq2Cr3+aq+2e-

Now, Cathode half-reaction can be written as,

Cu2+aq+2e-Cus

Overall reaction now written as adding both half-reactions,

2Cr2+aq+Cu2+s2Cr3+aq+Cus

Therefore, balanced equation for the overall reaction in given galvanic cell is,

2Cr2+aq+Cu2+s2Cr3+aq+Cus

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Most popular questions from this chapter

Question: A half-cell has a graphite electrode immersed in an acidic solution (pH0) of Mn2+(concentration (1.00M))in contact with solid MnO2. A second half-cell has an acidic solution (pH0) of H2O2(concentration (1.00M)in contact with a platinum electrode past which gaseous oxygen at a pressure of 1 atmis bubbled. The two half-cells are connected to form a galvanic cell.

(a) Referring to Appendix E, write balanced chemical equations for the half-reactions at the anode and the cathode and for the overall cell reaction.

(b) Calculate the cell potential.

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Could sodium be used as a sacrificial anode to protect the

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