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Prove that the probability to find an electron in 2pz orbital anywhere inx-y plane is zero. Also, determine the nodal planes for dxz and dx2-y2.

Short Answer

Expert verified

The nodal planes are two planes that contain the -axis at a 45° from the X-and Y-axes.

Step by step solution

01

Definition of the wave function

A mathematical representation of an electron in an orbital is a wave function. It is

created by multiplying the radial and angular wave functions.

02

Equation for the angular wave function of the 2pz orbital

The equation for the angular wave function of the 2pz orbital is as follows:

Ypz=34πcosθ

In the x-y coordinate system, the angle formed by the 2pz orbital will be π2, which is data-custom-editor="chemistry" 90°. In this case, θ has a value of 90.

03

Calculation of Ypz'  substitute the value in the preceding equation

Calculate Ypz' and substitute the value in the preceding equation for the angular component of the wave function:

Recall: θ=π2

Ypz=34πcosθ=34πcosπ2=34π×0=0θ=π2,cosθ=0

04

Stating the reason to prove that the probability of finding an electron in an 2pz  orbital anywhere in the -y plane is zero.

Since, the total wave function of an 2pz orbital is the product of a radial wave function and an angular wave function, the total wave function of an 2pz orbital will also be zero in the x-y plane.

Thus, the probability of finding an electron in a 2pz orbital anywhere in the x-y plane is zero.

For an atom, the radial part of wave functions is affected solely by r, while the angular part of wave functions is affected solely by the direction and shape of an orbital.

The region where the radial part of a wave function passes through zero is referred to as a radial node. Angular nodes or nodal planes are regions where the angular wave function passes through zero.

05

Specifying the nodal plane for dxzYdxz=154πsinθcosθcosϕ       =0     θ=π2,cosθ=0 

Therefore, the nodal planes are the y-zand x-yplanes

06

Specifying the nodal plane for dx2-y2

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