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Question: Tetraphenyl germane, (C6H5)4Ge,has a melting point of 232.5°C, and its enthalpy increasesby 106.7Jg-1during fusion. Calculate the molar enthalpy of fusion and molar entropy of fusion of tetraphenyl germane.

Short Answer

Expert verified

The molar enthalpy of fusion and molar entropy of fusion of tetraphenyl germane is80.39JK-1mol .

Step by step solution

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01

Given information

The melting point of tetraphenyl germane (C6H5)4Ge,Tf=232.5°Cand the enthalpy changes of fusion Hfus=106.7g-1.

02

Concept of molar entropy and enthalpy of fusion

The molar heat of fusion is divided by the melting point to get the entropy of fusion. The energy required to convert one mole of a substance from the solid to the liquid phase at constant temperature and pressure is known as the molar enthalpy of fusion.

03

Convert unit of temperature

The unit of temperature is converted from degree Celsius to kelvin as:

The melting point of tetraphenyl germane (C6H5)4Ge,Tf=232.5°C

localid="1663817125450" Tf=232.5+273.15Tf=505.65K

04

Calculate molar enthalpy of tetraphenyl germane

The molar mass of tetraphenyl germaneC6H54Ge:=4*((612.01)+(51))+72.5.

The molar mass of tetraphenyl germane C6H54Ge:=381.0gmol-1.

Thus, molar enthalpy changes of fusion of tetraphenyl germane =106.7*381.0

The molar enthalpy changes of fusion of tetraphenyl germane=4.065*104Jmol-1

05

Calculate molar entropy of fusion

The formula of Entropy of fusion is Sfus=Hfus/Tf.

Put the value of HfusandTf in above equation.
Sfus=4.065*104Jmol-1/505.65KSfus=80.39JK-1mol

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