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Use average bond enthalpies from the given data to estimate the change in enthalpy ΔHfor the reaction:C2H4(g)+H2(g)C2H6(g)

Short Answer

Expert verified

The answer is ΔH=492kJ.

Step by step solution

01

Given data

Bond

Enthalpy

C=C

615

H-H

436

C-H

413

C-C

348

02

Concept used

Enthalpy change is the amount of heat absorbed or evolved in a reaction when carried out at a constant pressure. It is generally calculated as the difference in energy required for bond breaking in a chemical reaction and energy gained in forming new bonds in the chemical reaction.

It is represented by ΔH.

By the use bond enthalpies the change in enthalpy has been calculated.

The structures of the participants of this reaction are given below.

The reactants:

C2H2: 6C-H Bonds, 4C-H bonds and H2:1H-H bond.

The product:

C2H6:6C-HBonds,andoneC-Cbond.

03

Calculate the enthalpy change of the products

By the use of bond enthalpies, the product enthalpy change has been calculated.

C2H6:6C-HBondsandoneC-Cbond.ΔBEproduct=ΔBE(C-C)+6×ΔBE(C-H)ΔBEproduct=348+6×413ΔBEproducts=2826kJ

04

Calculate the enthalpy change of the reactants

By the use of bond enthalpies, the product enthalpy change has been calculated.

C2H4:2C=CBonds,4C-HbondsandH2:1H-Hbond.ΔBEreactants=2×ΔBE(C=C)+4×ΔBE(C-H)+ΔBE(H-H)ΔBEreactants=2×615+4×413+436ΔBEreactants=3318kJ

05

Calculate the overall energy change

Overall energy:

ΔBEreactants=3318kJΔBEProducts=2826kJ

Apply these values to calculate the overall energy change.

ΔH=ΔBEreactants-ΔBEproductsΔH=3381-2826ΔH=492kJ

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