Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a general equation (using R to represent a general alkyl group) for the formation of an ester by the condensation of a tertiary alcohol with a carboxylic acid.

Short Answer

Expert verified

The general chemical equation of the formation of ester is as follows:

Step by step solution

01

Formation of esters

When carboxylic acids are heated with alcohols in the presence of catalysts, esters are formed. This process is known as esterification reaction. Water molecules are also formed along with esters.

02

Step 2: General equation for alcohols, acid and ester

Tertiary alcohols are the organic compounds in which the functional group, –OH is bonded to a carbon atom that is connected to three carbon groups. It has the general chemical formula, R13C-OH, where R1 is the carbon group or alkyl group.

Carboxylic acid has the chemical formula RCOOH, where R is an alkyl group.

Esters are formed by addition of both molecules, followed by the removal of water. So it has the chemical formula, R - CO - CR13 , where R,R1 may be same or different alkyl groups.

03

General chemical equation for ester formation

The general chemical equation of the formation of ester is given below:

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free