Question

Use the data in Table 3.1 to plot the logarithm of ionization energy versus the number of electrons removed for Ne. Describe the electronic structure of the Ne atom.

Short answer

The electronic structure of the Beryllium element is${\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{6}}$, and the graphical representation of the Logarithm of ionization energy versus the number of electrons removed from Neon (Ne) is

Step-by-step solution

The graphical representation of the Logarithm of ionization energy versus the number of electrons removed from the Neon (Ne) element.

Electronic structure of Neon (Ne) element.

The logarithm value ishigh. The graphical representation of the Logarithm of ionization energy versus thenumber of electrons removed from Neon (Ne) shows a dramatic increase between$\text{n = 8}$and$\text{n =9}$, which shows that the first$\left({\text{1}}^{\text{st}}\right)$ionization energy value is high.

The electronic configuration of the Neon (Ne) element is${\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{6}}$.