Question

Suppose a 0.100M solution of each of the following substances is prepared. Rank the pH of the resulting solutions from lowest to highest:

${\mathbf{\text{KF,NH}}}_{\mathbf{4}}\mathbf{\text{l}}\mathbf{,}\mathbf{\text{HBr}}\mathbf{,}\mathbf{\text{NaCl}}\mathbf{,}\mathbf{\text{LiOH}}$

Short answer

The lowest pH to the highest (acidic to basic) is

$\text{HBr}<N{H}_{4}I<NaCl<KF<LiOH$

Step-by-step solution

Concept used

Acid-base pH Concept:

The lower pH solution will be more acidic and also the higher pH, the solution will be more basic.

Given information from the question

Given:

$\text{c}\left(\text{solution}\right)=0.100\text{M}$

Arrange the resulting solutions' pH values from lowest to highest:

${\text{KF,NH}}_4\text{l},\text{HBr},\text{NaCl},\text{LiOH}$

Determine  pH of the resulting solutions from lowest  pH  to highest 

As we know that the lower pH the solution will be more acidic and also the higher pH, the solution will be more basic.

- KF is the salt made of a strong base and strong acid which makes it'sa pH neutral.

- NH₄I is the salt made of a weak base and strong acid which means it's

pH will be < 7, acidic.

- HBr is the strong acid which means that the pH < 7 , acidic.

- NaCl is the salt made of a strong base and strong acid which makes it's pH neutral, pH=7 .

-LiOH is the strong base which means that pH > 7, basic.

Sort the given examples from the lowest to the highest (acidic to basic)

The lowest pH to the highest (acidic to basic) is

$\text{HBr}<N{H}_{4}I<NaCl<KF<LiOH$