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Calculate the rms thermal noise associated with1.0MΩ load resistor operated at room temperature if an oscilloscope with a 1-MHz bandwidth is used. If the bandwidth is reduced to 100 Hz by what factor will the noise be reduced?

Short Answer

Expert verified

The rms of themal noise at 1 Mhz bandwidth isυ¯rms=1.28×104V

If the bandwidth reduced by 100 Mhz, the noise reduced by factor 100 times.

Step by step solution

01

Given information

The room temperature,T=298 K

The frequency bandwidth,Δf=1MHz

The resistance of the resistor,R=1.0MΩ

02

Step 2. Explanation

Thermal noise for a resistive circuit element can be given as

υ¯rms=4kTRΔf

Here,  k=Boltzmann'sconstant=1.38×1023J/KT=TemperatureinK, R=ResistanceinΩ,  and  Δf=Bandwidth

Substitutes the value in the above expression

υ¯rms=4kTRΔf=4×1.38×1023×298×1×106×1.0×106υ¯rms=1.28×104V

ForΔf=100 Hz

υ¯rms,2=4kTRΔfυ¯rms,2=4×1.38×1023×298×1×106×100υ¯rms,2=1.28×106V

Noise reduction factor is

υ¯rmsυ¯rms,2=1.28×104V1.28×106V=100

Therefore, the rms of themal noise at 1 Mhz bandwidth isυ¯rms=1.28×104V

If the bandwidth reduced by 100 Mhz, the noise reduced by factor 100 times.

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