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Estimate the standard deviation and the relative standard deviation associated with counts of (a) 100, (b) 850, (c) 8.00X103, and (d) 4.00X104.

Short Answer

Expert verified

Part (a)σM=100=10,σR=10%

Part (b)σM=850=29.15,σR=3.43%

Part (c)σM=8.00×103=2828.4,σR=0.0354%

Part (d)σM=4.00×104=20000,σR=0.005%

Step by step solution

01

Introduction

Standard deviation - The standard deviation, which is determined as a percentage of the mean, is the most commonly used quantitative measure of precision.

Relative standard deviation - Calculating the dispersion of a set of values in relation to the mean, we may analyses the precision in a set of values using relative standard deviation.

02

Concept

The standard deviation can be calculated using the formula below:

σM=M

The formula for calculating the relative standard deviation is:

σR=σmMσR=MM

03

Solution to part (a)

The standard deviation formula is as follows:

σM=M

Where,

M=count's number

σM=standard deviation

The relative standard deviation formula is as follows:

σR=σMMσR=MM

Where,

σR=relative standard deviation

Given is -

Count =100

As a result, the standard deviation is

role="math" localid="1646072762981" σM=100=10

Now we'll look at the relative standard deviation-

Count=600

Therefore,

σR=MM=1M

Where,

role="math" localid="1646072801916" M=100=10σR=110=0.1σR%=110×100=10%σR=10%

04

Solution to part (b)

The standard deviation is calculated using the formula:

σM=M

Where,

M=count's number

σM=standard deviation

The relative standard deviation formula is as follows:

σR=σMMσR=MM

Where,

σR=relative standard deviation

Given is -

count =850

As a result, the standard deviation is

role="math" localid="1646072862998" σM=850=29.15

Now we'll look at the relative standard deviation-

Count =850

Therefore,

σR=MM=1M

Where,

role="math" localid="1646072919121" M=850=29.15σR=129.15=0.0343σR%=0.0343×100=3.43%σR=3.43%

05

Solution to part (c)

The standard deviation formula is as follows:

σM=M

Where,

M=count's number

localid="1646073100230" σM=standard deviation

The relative standard deviation formula is as follows:

σR=σMMσR=MM

Where,

σR=relative standard deviation

Given is -

Count=8.00×103

As a result, the standard deviation -

localid="1646072949454" σM=8.00×103=2828.4

Now we'll look at the relative standard deviation-

Count=8.00×103

Therefore,

σR=MM=1M

Where,

localid="1646072975876" M=8.00×103=2828.4σR=12828.4=0.000354σR%=0.000354×100=0.0354%σR=0.0354%

06

Solution to part (d)

The standard deviation formula is as follows:

σM=M

Where,

M=count's number

σM=standard deviation

The relative standard deviation formula is as follows:
σR=σMMσR=MM

Where,

σR=relative standard deviation

Given is -

Count=4.00×104

As a result, the standard deviation -
role="math" localid="1646073007586" σM=4.00×104=20000

Now we'll look at the relative standard deviation-

Count=4.00×104

Therefore,

σR=MM=1M

Where,

role="math" localid="1646073034836" M=4.00×104=20000σR=120000=0.00005σR%=0.000054×100=0.005%σR=0.005%

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Most popular questions from this chapter

(a) By referring to a reference on NAA or by using an Internet search engine to find the information, describe in some detail the instrumental and radiochemical differences between prompt gamma-ray neutron activation and delayed gamma-ray neutron activation.

(b) What are the types of elements for which prompt gamma-ray activation analysis is most applicable?

(c) Why is delayed gamma-ray emission most often used in NAA?

(d) Why is NAA considered to be a very selective and sensitive method?

(e) A crystal of potassium fluoride is to be studied via NAA. The following table summarizes the behavior of all naturally occurring isotopes in the crystal.

19F, 20Ne, 39K, 41K, and 42Ca are stable, and we will assume that 40K is also stable because it has a half- life of 1.3 * 109 years. What sort of irradiation and detection sequence would you use if you wanted to base your analysis on fluorine?

(f) What sort of irradiation and detection sequence would you use if you wanted to base the analysis on potassium?

(g) Refer to part (e) and calculate the activity due to 20F and 42K in a 58-mg (1.0-millimole) sample of pure potassium fluoride that has been irradiated for 60 s. The thermal neutron cross sections for 19F and 41K

are 0.0090 * 10-24 cm2 and 1.1 * 10-24 cm2 , respectively. Assume a flux density of 1.0 * 10-3 neutrons cm-2s-1.

(h) Find a method in the literature that describes the use of NAA for determining selenium in freshwater ecosystems. Describe the method in detail. Include the neutron source, the irradiation time, and the calculations used. Give the advantages and disadvantages of the method over other analytical techniques.

Calculate the fraction of each of the following radionuclides that remains after 1 day, 2 days, 3 days, and 4 days (half-lives are given in parentheses): iron-59 (44.51 days), titanium-45 (3.078 h), calcium-47 (4.536 days), and phosphorus-33 (25.3 days).

For a radionuclide that obeys Equation 32-3,

(a) find the percentage of the nuclide remaining after a time equal to 1/λ.

(b) What time in units of 1/λwould be required for 90%of the nuclide to decay?

(c) What time in units of 1/λwould be required for99% of the nuclide to decay?

A 2.00-mL solution containing 0.113 microcuries per milliliter of tritium was injected into the bloodstream

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The background counting rate of a laboratory was found to be approximately 9 cpm when measured over a 3-min period. The goal is to keep the relative standard deviation of the corrected counting rate at less than 5% (sRc /Rc , 0.05). What total number of counts should be collected if the total counting rate is (a) 50 cpm and (b) 300 cpm?

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