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Describe the difference between gaseous field ionization sources and field desorption sources.

Short Answer

Expert verified

Mostly ion sources are categorized as two types; they are gas phase sources and desorption sources. In gas phase sources, the sample is first vaporized and then ionized. In desorption sources, the solid or liquid sample is converted directly into gaseous ions. Here, field ionization is belongs to gas phase sources and field desorption is belongs to desorption sources.

Step by step solution

01

Common difference

A high-potential electric field is applied to an emitter with a sharp surface, such as a razor blade, or, more typically, a filament from which small "whiskers" have developed, in the field desorption.
The sample is first volatilized and then transferred to the ionisation region for ion production in a gaseous ionisation source.
02

Differences

S.No

Field ionization

sources(FI)

Field desorption

sources(FD)

1.
The sample is directly evaporated from the insection probe or gas inlet. So, the gaseous molecules reach the emitter and then they are ionized by electron tunneling.
The sample is deposited at the emitter which is biased to high potential when a current is passed through emitter to heat up the filament. So, the emitter current increases gradually as results the sample evaporates from emitter into gas phase.
2.It is mostly used for small organic molecules and some petrochemical reactions.

It is mostly used for thermally stable nonvolatile, polar organic, and organometallic compounds.
3.There is no chemical reaction occur
There is no chemical reaction occur
4.Mass spectrum range is low nearly less than 1000 Da
Mass spectrum range is high approximately between 2000 to 3000 Da
5.Mixture of ion species are recognized by this sources per molecules at a time.
One moelcular ion species is recognized by this sources per moleucle at one time

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Most popular questions from this chapter

What mass differences can just be resolved at m values of 100,1000,2000,3000and 5000if the mass spectrometer has a resolution of

(a) 500(b) 1000(c) 3000(d) 5000?

The following figure is a simplified diagram of a commercially available EI source.
(a) What voltage must be applied between the filament and target so that electrons interacting with molecules
at the point marked SS (sample source) will have 70 eV of kinetic energy?
(b) What will happen to a molecule that diffuses toward the filament and is ionized at point P?

In a magnetic sector (single-focusing) mass spectrometer, it might be reasonable under some circumstances to monitor one m/zvalue, to then monitor a second m/z, and to repeat this pattern in a cyclic manner.

Rapidly switching between two accelerating voltages while keeping all other conditions constant is called

peak matching.

(a) Derive a general expression that relates the ratio of the accelerating voltages to the ratio of the

corresponding m/zvalues.

(b) Use this equation to calculate m/zof an unknown peak if m/zof the ion used as a standard, CF3+is 69.00and the ratio of Vunknown/Vstandardis 0.965035.

(c) Based on your answer in part (b), and the assumption that the unknown is an organic compound that has a mass of 143, draw some conclusions about your answer in part (b), and about the compound.

How do gaseous and desorption sources differ? What are the advantages of each?

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