Question

The same polar compound is gas chromatographed on an $SE-30$column and then on a Carbowax $20\mathrm{M}$(very polar column). How will $K=c_{\mathrm{S}}/c_{\mathrm{M}}$vary between the two columns?

Short answer

If we've $SE-30$which is incredibly non-polar and that we have polar analyte, we'll have more analyte within the mobile phase which must be polar if column is non-polar which increases $C_M$and reduces $\mathrm{K}$.And if we've Carbowax $20\mathrm{M}$which is polar and that we have polar analyte, he is going to be more concentrated in stationary phase, and increase in $c_S$leads to increase in $\mathrm{K}$.

Step-by-step solution

Formula.

Define the formula $\left(1\right)$:

$K=\frac{c_S}{c_M}$

Variation between two columns.

where $c_S$is concentration of the analyte in stationary phase and $c_M$is concentration in mobile phase.

Therefore, if we've $SE-30$which is incredibly non-polar and that we have polar analyte, we will have more analyte within the mobile phase which must be polar if column is non-polar which increases $c_M$and reduces$K$

And if we've Carbowax $20M$which is polar and that we have polar analyte, he are more concentrated in stationary phase, and increase in $c_S$ends up increase in $\mathrm{K}$.