Question

Show that the data in the last column of Table 2-1 are correct.

Short answer

The data in table 2-1 is correct.

Step-by-step solution

Given information

Table 2-1 is shown below

Calculations:

The expression for relative error is given by:

$E=-\frac{R}{R_{in}+R}\times 100\%$

where R is the resistance of the source and R_in is the resistance of the meter.

$$\begin{gathered} \left(i\right)Row1 \\ E=-\frac{20}{10+20}\times 100\%=-\frac{20}{30}\times 100\% \\ E=-67\% \\ \left(ii\right)Row2 \\ E=-\frac{20}{50+20}\times 100\%=-\frac{20}{70}\times 100\% \\ E=-29\% \\ \left(iii\right)Row3 \\ E=-\frac{20}{500+20}\times 100\%=-\frac{20}{520}\times 100\% \\ E=-3.8\% \\ \left(iv\right)Row4 \\ E=-\frac{20}{1000+20}\times 100\% \\ E\approx -2\% \\ \left(v\right)Row5 \\ E=-\frac{20}{10000+20}\times 100\% \\ E=-0.2\% \end{gathered}$$

Since the calculated percentage error matches with the error data given in the table. It implies that the last column of the table is correct.