Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The spectrum in Figure 17-22 is that of a nitrogen-containing substance that boils at 97°C. What is the compound?

Short Answer

Expert verified

The compound is propane nitrile (CH3CH2CN).

Step by step solution

01

Step 1. Given information

Determine the compound that contains nitrogen and boils at 97°C.

02

Step 2. Explanation

From the graph, the range of the functional group region lies between 3600cm-1-1250cm-1.

The following function group is present in the compound.

2900cm-1-3100cm-1:Nbond2200cm-1-2300cm-1:C-Hstretching1400cm-1-1450cm-1:C-Hbending

So the compound is propanenitrile (CH3CH2CN).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An empty cell exhibited 17.5 interference fringes in the region of 1050 to 1580 cm-1. What was the path length of the cell?

Estimate the thickness of the polystyrene film that yielded the spectrum shown in Figure 16-1.

The spectrum in Figure 17-19 was obtained for a liquid with the empirical formula of C3H6O. Identify the compound.

(a) Consider an ATR experiment with a sample having a refractive index of 1.03 at 2000 cm-1. The ATR crystal was AgCl with a refractive index of 2.00 at this wavelength. For an angle of incidence of 45°, what is the effective penetration depth of the evanescent wave? How would the penetration depth change if the angle were changed to 60°?
(b) For the same experiment in part (a) and a 60° incidence angle, find the penetration depths for sample refractive indexes varying from 1.00 to 1.70 in steps of 0.10. Plot penetration depth as a function of refractive index. Determine the refractive index for which the penetration depth becomes zero. What happens at this point?
(c) For a sample with a refractive index of 1.37 at 2000 cm-1 and an incidence angle of 45°, plot the penetration depth versus the ATR crystal refractive index. Vary the crystal refractive index over the range of 2.00 to 4.00 in steps of 0.25. Which crystal, AgCl (nc5 2.00) or Ge (nc 5 4.00), gives the smaller penetration depth? Why?
(d) An aqueous solution with a refractive index of 1.003 is measured with an ATR crystal with a refractive index of 2.8. The incidence angle is 45°. What is the effective penetration depth at 3000 cm-1, 2000 cm-1, and 1000 cm-1? Is absorption by the aqueous solvent as much of a problem in ATR as in normal IR absorption measurements? Why or why not?
(e) Work by S. Ekgasit and H. Ishida (S. Ekgasit and H. Ishida, Appl. Spectrosc., 1996, 50, 1187; Appl. Spectrosc., 1997, 51, 461) describes a new method to obtain a depth profile of a sample surface using ATR spectroscopy. Describe the principles of this new approach. Why are spectra taken with different degrees of polarization? What is the complex index of refraction?

Why do IR spectra seldom show regions at which the transmittance is 100%?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free