Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Why is the CaOH spectrum in Figure 8-8 so much broader than the sodium emission line shown in Figure 8-4?

Short Answer

Expert verified

The spectrum of CaOH is broader due to transitions between vibrational and rotational states, whereas shifts between electronic energy levels occur in sodium.

Step by step solution

01

Given Information

CaOH spectrum is so much broader than the sodium emission line.

02

Step2. Explanation

Calcium hydroxide, or CaOH, is an ionic molecule with vibrational and rotational levels. In the case of the CaOH molecule, there are broad line spectra due to transitions between vibrational and rotational states.

Transitions between the vibrational and rotational states are not possible in the case of sodium. As a result, they occur between electronic energy states, resulting in a line spectrum.

03

Conclusion

The spectrum of CaOH is broader due to transitions between vibrational and rotational states, which is not possible in sodium.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In high-temperature sources, sodium atoms emit a doublet with an average wavelength of 1139 nm. The transition responsible is from the 4s to 3p state. Set up a spreadsheet to calculate the ratio of the number of excited atoms in the 4s state to the number in the ground 3s state over the temperature range from an acetylene-oxygen flame (3000ยฐC) to the hottest part of an inductively coupled plasma source 8750ยฐC).

In a study of line broadening mechanisms in low-pressure laser-induced plasmas, Gornushkina et al.10 present the following expression for the half width for Doppler broadening โˆ†ฮปDof an atomic line.

โˆ†ฮปD(T)=ฮป08kTln2Mc2

where ฮป0is the wavelength at the center of the emission line, k is Boltzmannโ€™s constant, T is the absolute temperature, M is the atomic mass, and c is the velocity of light. Ingle and Crouch11 present a similar

equation in terms of frequencies.

โˆ†vD=22(ln2)kTM1/2vmc

where โˆ†vDis the Doppler half width and vmis the frequency at the line maximum.

(a) Show that the two expressions are equivalent.

(b) Calculate the half width in nanometers for Doppler broadening of the 4sโ†’4p transition for atomic nickel at 361.939 nm (3619.39 ร…) at a temperature of 20,000 K in both wavelength and frequency units.

(c) Estimate the natural line width for the transition in (b) assuming that the lifetime of the excited state is 5ร—10-8s.

(d) The expression for the Doppler shift given in the chapter and in Problem 8-8 is an approximation that works at relatively low speeds. The relativistic expression for the Doppler shift is

โˆ†ฮปฮป=1c-vc+v-1

Show that the relativistic expression is consistent with the equation given in the chapter for low atomic

speeds.

(e) Calculate the speed that an iron atom undergoing the 4s โ†’4p transition at 385.9911 nm (3859.911 ร…) would have if the resulting line appeared at the rest wavelength for the same transition in nickel.

(f) Compute the fraction of a sample of iron atoms at 10,000 K that would have the velocity calculated in (e).

(g) Create a spreadsheet to calculate the Doppler half width โˆ†ฮปDin nanometers for the nickel and iron lines cited in (b) and (e) from 3000โ€“10,000 K.

(h) Consult the paper by Gornushkin et al. (note 10) and list the four sources of pressure broadening that they describe. Explain in detail how two of these sources originate in sample atoms.

For Na atoms and Mg+ ions, compare the ratios of the number of atoms or ions in the 3p excited state to the number in the ground state in

(a) a natural gasโ€“air flame (1800 K).

(b) a hydrogen-oxygen flame (2950 K).

(c) an inductively coupled plasma source (7250 K).

What determines natural line widths for atomic emission and absorption lines? About how broad are these widths, typically?

In the concentration range of 500 to 2000 ppm of U, there is a linear relationship between absorbance at 351.5 nm and concentration. At lower concentrations, the relationship is nonlinear unless about 2000 ppm of an alkali metal salt is introduced into the sample. Explain.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free