Problem 1
If \(0.50\) mole of \(\mathrm{BaCl}_{2}\) is mixed with \(0.20 \mathrm{~mol}\) of \(\mathrm{Na}_{3} \mathrm{PO}_{4}\), the maximum number of moles of \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) that can be formed is a. \(0.10\) b. \(0.20\) c. \(0.30\) d. \(0.40\)
Problem 2
One mole of \(\mathrm{N}_{2} \mathrm{H}_{4}\) loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in \(\mathrm{Y}\) ? (There is no change in the oxidation state of hydrogen). a. \(+2\) b. \(-2\) c. \(+3\) d. \(+4\)
Problem 4
In which mode of expression, the concentration of a solution remains independent of temperature? a. Formality b. Molality c. Molarity d. Normality
Problem 5
One litre hard water contains \(12.00 \mathrm{mg} \mathrm{Mg}^{2+}\). Milliequivalents of washing soda required to remove its hardness is a. 1 b. \(12.16\) c. \(1 \times 10^{-3}\) d. \(12.16 \times 10^{-3}\)
Problem 9
The number of gram-molecule of oxygen which contain \(6.02 \times 10^{24} \mathrm{CO}\) molecules is a. \(10 \mathrm{~g}\) molecule b. \(5 \mathrm{~g}\) molecule c. \(1 \mathrm{~g}\) molecule d. \(0.5 \mathrm{~g}\) molecule
Problem 10
The mass of \(1 \times 10^{22}\) molecules of \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is a. \(41.59 \mathrm{~g}\) b. \(415.9 \mathrm{~g}\) c. \(4.159 \mathrm{~g}\) d. none of these
Problem 11
The weight of one molecule of a compound \(\mathrm{C}_{60} \mathrm{H}_{122}\) is a. \(1.2 \times 10^{-20} \mathrm{gm}\) b. \(1.4 \times 10^{-21} \mathrm{gm}\) c. \(5.025 \times 10^{25} \mathrm{gm}\) d. \(6.023 \times 10^{23} \mathrm{gm}\)
Problem 12
The percentage weight of \(\mathrm{Zn}\) in white vitriol \(\left[\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\right]\) is approximately equal to \((\mathrm{Zn}=65\) \(\mathrm{S}=32, \mathrm{O}=16\) and \(\mathrm{H}=1\) ) a. \(33.65 \%\) b. \(32.56 \%\) c. \(23.65 \%\) d. \(22.65 \%\)
Problem 13
The percentage weight of \(\mathrm{Zn}\) in white vitriol \(\left[\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\right]\) is approximately equal to \((\mathrm{Zn}=65\) \(\mathrm{S}=32, \mathrm{O}=16\) and \(\mathrm{H}=1\) ) a. \(33.65 \%\) b. \(32.56 \%\) c. \(23.65 \%\) d. \(22.65 \%\)
Problem 15
Number of atoms in \(4.25 \mathrm{gm}\) of \(\mathrm{NH}_{3}\) is approximately a. \(6 \times 10^{23}\) b. \(15 \times 10^{23}\) c. \(1.5 \times 10^{23}\) d. \(2.5 \times 10^{25}\)
