Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The adsorption of ethyl chloride on a sample of charcoal at \(0^{\circ} \mathrm{C}\) measured at several different pressures is as follows: $$\begin{array}{rc} \mathbf{P}_{C_{2} H_{5} C l}(\text { Torr }) & V_{\text {ads}}(\mathbf{m L}) \\\ \hline 20 & 3.0 \\ 50 & 3.8 \\ 100 & 4.3 \\ 200 & 4.7 \\ 300 & 4.8 \end{array}$$ Using the Langmuir isotherm, determine the fractional coverage at each pressure and \(V_{m}\)

Short Answer

Expert verified
Using the Langmuir isotherm, we calculated the fractional coverage θ for each pressure using the equation \(θ = \frac{KP}{1+KP}\). We then plotted the variables \(\frac{V_{ads}}{V_m – V_{ads}}\) and pressures to observe a linear relationship. After performing a linear regression on the plotted datapoints, we determined the Langmuir constant K from the slope and calculated Vm by finding the x-intercept. Finally, we computed the final fractional coverage θ at each pressure using the Langmuir isotherm equation.

Step by step solution

01

Compute fractional coverage using the Langmuir isotherm equation

Since the pressures are given and we have the equation, compute the fractional coverage for each pressure P using the equation: θ = \(\frac{KP}{1+KP}\) At each pressure, the corresponding V_ads is given. We can use a linearized form of the Langmuir equation: \[\frac{V_{ads}}{V_m – V_{ads}} = \frac{1}{KP}\] Calculate the variable \(\frac{V_{ads}}{V_m – V_{ads}}\) for each pressure using the adsorption volume V_ads. 2.
02

Plot the variables

Plot the variables \(\frac{V_{ads}}{V_m – V_{ads}}\) on the y-axis and the pressures on the x-axis as scattered points. We should observe a linear relationship between these variables. 3.
03

Calculate the slope and intercept using linear regression

Perform a linear regression on the plotted datapoints to estimate the slope and intercept of the best fitting line through the origin. Use a statistical software or calculator for this purpose. 4.
04

Determine the K value

The inverse of the slope from the linear regression will give us the Langmuir constant (K). \(K = \frac{1}{\mathrm{slope}}\) 5.
05

Calculate Vm

After determining the value of K, calculate Vm by finding the value of the x-intercept using the linear regression, when \( \frac{V_{ads}}{V_m – V_{ads}} = 0 \). \(V_m\) will be the reciprocal of the intercept value. 6.
06

Compute final fractional coverage

Now that we have K and Vm, compute the final fractional coverage θ at each pressure using the Langmuir isotherm equation: \(θ = \frac{KP}{1+KP}\) From these steps, we have been able to determine the fractional coverage at each pressure and the Vm using the Langmuir isotherm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Adsorption of Gases
Adsorption is a process where molecules of a gas accumulate on the surface of a solid or a liquid. This occurs because of the intermolecular forces between the gas molecules and the surface atoms or molecules. In physical chemistry, this phenomenon is crucial to understanding how various substances interact with surfaces and is widely studied in the context of catalysis, separation processes, and environmental science.

When we analyze the adsorption of gases like ethyl chloride on charcoal, we consider factors such as temperature, pressure, and the properties of both the gas and the adsorbent surface. The amount of gas adsorbed can be quantified volumetrically, as in the exercise example. Here, the adsorption increases with pressure but to a lesser extent as the pressure continues to increase. This non-linear relationship between pressure and adsorption volume is a characteristic of many adsorption processes and is described by the Langmuir isotherm.
Fractional Coverage
Fractional coverage (denoted as \( \theta \)) is a key concept in studying the adsorption of gases. It represents the fraction of the adsorption sites on a surface that are occupied by adsorbate molecules. In practical terms, fractional coverage tells us how much of the surface is 'covered' by the adsorbed gas.

In the exercise given, the Langmuir isotherm equation \( \theta = \frac{KP}{1+KP} \) is used to calculate the fractional coverage at various pressures, where \( K \) is the Langmuir constant and \( P \) is the pressure of the adsorbing gas. A key feature of the Langmuir model is its assumption that adsorption occurs at specific homogeneous sites on the surface, and once a site is occupied, no further adsorption can happen at that site. This aids in understanding the behavior of adsorption at both low and high pressures and informs us of how efficient the adsorbent material is at various conditions.
Physical Chemistry
Physical chemistry is the branch of chemistry that focuses on the understanding of the physical properties of molecules, the forces that act upon them, and the physical laws that govern their behavior. It blends principles of physics and chemistry to explain how chemical systems work and how they change with respect to time and energy. The study of adsorption is highlighted in physical chemistry because it involves the understanding of intermolecular forces, thermodynamics, and kinetics.

In the context of the exercise, utilizing the Langmuir isotherm requires an understanding of the physical interaction between the gas molecules and the adsorbent surface. By combining experimental data with physical chemistry theory, we find a practical application: determining how much of a gas will be adsorbed at different pressures, and consequently, we can predict how a system will behave in real-world scenarios. Through careful analysis and mathematical representation, such as the linearization of the Langmuir equation, physical chemists can elucidate the characteristics of the adsorption process.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the unimolecular isomerization of cyclobutane to butylene, the following values for \(k_{u n i}\) as a function of pressure were measured at \(350 \mathrm{K}\) \\[ \begin{array}{lcccc} \boldsymbol{P}_{\mathbf{0}}(\mathbf{T o r r}) & 110 & 210 & 390 & 760 \\ \boldsymbol{k}_{\boldsymbol{u n i}}\left(\mathbf{s}^{-1}\right) & 9.58 & 10.3 & 10.8 & 11.1 \end{array} \\] Assuming that the Lindemann mechanism accurately describes this reaction, determine \(k_{1}\) and the ratio \(k_{-1} / k_{2}\)

Consider the collision-induced dissociation of \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) via the following mechanism: \\[ \begin{array}{l} \mathrm{N}_{2} \mathrm{O}_{5}(g)+\mathrm{N}_{2} \mathrm{O}_{5}(g) \frac{k_{1}}{\overline{k_{-1}}} \mathrm{N}_{2} \mathrm{O}_{5}(g)^{*}+\mathrm{N}_{2} \mathrm{O}_{5}(g) \\ \mathrm{N}_{2} \mathrm{O}_{5}(g) * \stackrel{k_{2}}{\longrightarrow} \mathrm{NO}_{2}(g)+\mathrm{NO}_{3}(g) \end{array} \\] The asterisk in the first reaction indicates that the reactan is activated through collision. Experimentally it is found that the reaction can be either first or second order in \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) depending on the concentration of this species. Derive a rate law expression for this reaction consistent with this observation.

The Rice-Herzfeld mechanism for the thermal decomposition of acetaldehyde \(\left(\mathrm{CH}_{3} \mathrm{CO}(g)\right)\) is \\[ \begin{array}{l} \mathrm{CH}_{3} \mathrm{CHO}(g) \stackrel{k_{1}}{\longrightarrow} \mathrm{CH}_{3} \cdot(g)+\mathrm{CHO} \cdot(g) \\ \mathrm{CH}_{3} \cdot(g)+\mathrm{CH}_{3} \mathrm{CHO}(g) \stackrel{k_{2}}{\longrightarrow} \mathrm{CH}_{4}(g)+\mathrm{CH}_{2} \mathrm{CHO} \cdot(g) \\ \mathrm{CH}_{2} \mathrm{CHO} \cdot(g) \stackrel{k_{3}}{\longrightarrow} \mathrm{CO}(g)+\mathrm{CH}_{3} \cdot(g) \\ \mathrm{CH}_{3} \cdot(g)+\mathrm{CH}_{3} \cdot(g) \stackrel{k_{4}}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{6}(g) \end{array} \\] Using the steady-state approximation, determine the rate of methane \(\left(\mathrm{CH}_{4}(g)\right)\) formation.

Reciprocal plots provide a relatively straightforward way to determine if an enzyme demonstrates Michaelis-Menten kinetics and to determine the corresponding kinetic parameters. However, the slope determined from these plots can require significant extrapolation to regions corresponding to low substrate concentrations. An alternative to the reciprocal plot is the Eadie- Hofstee plot in which the reaction rate is plotted versus the rate divided by the substrate concentration and the data are fit to a straight line. a. Beginning with the general expression for the reaction rate given by the Michaelis-Menten mechanism: \\[ R_{0}=\frac{R_{\max }[\mathrm{S}]_{0}}{[\mathrm{S}]_{0}+K_{m}} \\] rearrange this equation to construct the following expression, which is the basis for the Eadie-Hofstee plot: \\[ R_{0}=R_{\max }-K_{m}\left(\frac{R_{0}}{[S]_{0}}\right) \\] b. Using an Eadie-Hofstee plot, determine \(R_{\max }\) and \(K_{m}\) for hydrolysis of sugar by the enzyme invertase using the following data: $$\begin{array}{cc} \text { [Sucrose ] }_{\mathbf{0}}(\mathbf{M}) & \mathbf{R}_{\mathbf{0}}\left(\mathbf{M} \mathbf{~ s}^{-\mathbf{1}}\right) \\ \hline 0.029 & 0.182 \\ 0.059 & 0.266 \\ 0.088 & 0.310 \\ 0.117 & 0.330 \\ 0.175 & 0.362 \\ 0.234 & 0.361 \end{array}$$

For phenanthrene, the measured lifetime of the triplet state \(\tau_{p}\) is \(3.3 \mathrm{s}\), the fluorescence quantum yield is \(0.12,\) and the phosphorescence quantum yield is 0.13 in an alcohol-ether glass at \(77 \mathrm{K}\). Assume that no quenching and no internal conversion from the singlet state occurs. Determine \(k_{p}, k_{i s c}^{T},\) and \(k_{i s c}^{S} / k_{f}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free