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An experiment is performed on the following parallel reaction: Two things are determined: (1) The yield for B at a given temperature is found to be 0.3 and (2) the rate constants are described well by an Arrhenius expression with the activation to \(\mathrm{B}\) and \(\mathrm{C}\) formation being 27 and \(34 \mathrm{kJ} \mathrm{mol}^{-1}\), respectively, and with identical preexponential factors. Demonstrate that these two statements are inconsistent with each other.

Short Answer

Expert verified
The given conditions state that the yield for B is 0.3, and the rate constants for B and C formation are governed by an Arrhenius expression with activation energies of 27 kJ/mol and 34 kJ/mol, respectively, and identical preexponential factors. By substituting the rate constant expressions into the equation for the yield of B and cancelling out the preexponential factor, we arrive at an equation involving both activation energies and the temperature. Rewriting the equation, it shows no contradictions or inconsistencies, meaning that the given yield and rate constant conditions are not inconsistent with each other for this parallel reaction.

Step by step solution

01

Understand the parallel reaction and given conditions

A parallel reaction involves two or more reactions occurring simultaneously, sharing a common reactant. For this exercise, we are given: 1. The yield for product B at a given temperature is 0.3, which means that 30% of the reactants are converted to B while the remaining 70% are converted to C. 2. The rate constants for B and C formation are described by an Arrhenius expression with activation energies of 27 kJ/mol and 34 kJ/mol, respectively. Furthermore, the preexponential factors for both B and C are identical in their rate constant expressions.
02

Write the rate constants for B and C formation

The Arrhenius expression relates the rate constant k of a reaction with the temperature T, activation energy E, and preexponential factor A. The Arrhenius equation is given by: \(k = Ae^{-E/RT}\) Where R is the gas constant (8.314 J/mol-K). Since we know the activation energies and that the preexponential factors A are identical for both B and C formation, we can write their rate constants as: \(k_B = Ae^{-27\text{ kJ/mol}/RT}\) \(k_C = Ae^{-34\text{ kJ/mol}/RT}\)
03

Define the yield in terms of rate constants

The yield for B can be defined as the proportion of reactants which form B. Mathematically, this can be represented as: \(\text{Yield for B} = \frac{k_B}{k_B + k_C}\) Given that the yield for B is 0.3: \(\frac{k_B}{k_B + k_C} = 0.3\)
04

Substitute the rate constants in the yield equation and show inconsistency

Now, we substitute the rate constant expressions from Step 2 into the yield equation from Step 3: \(\frac{Ae^{-27\text{ kJ/mol}/RT}}{Ae^{-27\text{ kJ/mol}/RT} + Ae^{-34\text{ kJ/mol}/RT}} = 0.3\) Since the preexponential factor A is identical for both B and C formation, we can cancel it out from the equation: \(\frac{e^{-27\text{ kJ/mol}/RT}}{e^{-27\text{ kJ/mol}/RT} + e^{-34\text{ kJ/mol}/RT}} = 0.3\) To show inconsistency, we should reach a contradiction in this equation. Let's find the term \( \frac{e^{-27\text{ kJ/mol}/RT}}{e^{-34\text{ kJ/mol}/RT}} \): \(\frac{e^{-27\text{ kJ/mol}/RT}}{e^{-34\text{ kJ/mol}/RT}} = e^{(34 - 27)\text{ kJ/mol}/RT} = e^{7\text{ kJ/mol}/RT}\) Now, let's set \(x = e^{7\text{ kJ/mol}/RT}\) and rewrite our main equation: \(\frac{1}{1 + x} = 0.3\) Solve for x: \(x = \frac{1 - 0.3}{0.3} = \frac{0.7}{0.3} = \frac{7}{3}\) Since we derived a positive value for x, and R and T are always positive, there is no contradiction in the equation. Therefore, there is no inconsistency between the given yield and rate constant conditions for this parallel reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arrhenius Equation
The Arrhenius equation is a fundamental formula used to describe how the rate of a chemical reaction changes with temperature. It was proposed by Svante Arrhenius in the late 19th century and has become a central tool in the study of reaction kinetics. The equation is expressed as:

[k = Ae^{-E/RT}]
Here, k represents the rate constant of the reaction, A is the preexponential factor or frequency factor, E stands for the activation energy of the reaction, R is the universal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin. The preexponential factor reflects the number of collisions resulting in a reaction per unit of time, and the exponential term accounts for the fraction of those collisions that have sufficient energy to overcome the energy barrier, known as the activation energy.

To explore the behavior of a chemical reaction with changing temperature, the Arrhenius equation shows that as temperature increases, the rate constant k also increases, implying a faster reaction. This is because a higher temperature means more molecules have sufficient kinetic energy to overcome the activation barrier and react.

When comparing reactions with different activation energies but identical preexponential factors, we can determine their relative rates at a given temperature using the Arrhenius equation. An increase in activation energy leads to a decrease in the rate constant, which means the reaction is slower.
Activation Energy
Activation energy (E) is a crucial concept in chemical kinetics. It refers to the minimum energy that reacting particles must possess for a reaction to occur. Essentially, it is the energy barrier that reactants must overcome to transform into products.

The relevance of activation energy within the context of the Arrhenius equation is that it directly impacts the rate at which a reaction occurs. A lower activation energy corresponds to more particles having enough energy to react, resulting in a higher reaction rate. Conversely, a higher activation energy suggests that fewer particles can react, indicating a slower reaction.

In the scenario of parallel reactions, where different products are formed from the same reactant, the difference in activation energies for the formation of products B and C dictates the preference: the route with lower activation energy is typically favored. However, if there is an inconsistency, such as an unexpected yield of one product, it may suggest that other factors are influencing the reaction, such as a difference in preexponential factors or additional reaction mechanisms at play.
Rate Constants
Rate constants (k) are an intrinsic part of the Arrhenius equation and are fundamental to the study of reaction rates. They represent the proportionality factor that connects the reaction rate to the concentrations of reactants.

The significance of a rate constant lies in its ability to capture the essence of a reaction's kinetics: it determines how quickly a reaction will progress under certain conditions. The magnitude of the rate constant can be influenced by several factors, including temperature, pressure, and the presence of catalysts. As discussed, temperature has a direct and substantial effect on the rate constant through the Arrhenius equation, whereby an increase in temperature typically increases the value of k.

In parallel reactions, each pathway has its own rate constant and activation energy, and the yield of each product depends on these constants. The exercise underlines the concept that the rate constant expressions incorporate both the frequency of the reactants' collisions and the fraction that results in a successful reaction. It emphasizes that if a reaction pathway has a significantly different rate constant, it could lead to an inconsistency with the expected chemical yield. This underlines the importance of accurately determining and comparing rate constants when investigating chemical reactions.
Chemical Yield
Chemical yield pertains to the efficiency of a chemical reaction, defined as the amount of product formed relative to the theoretical maximum possible or relative to the amount of reactants used. It is usually expressed as a percentage.

In the context of our parallel reaction exercise, the yield for product B is given as 0.3 (or 30%), indicating that 30% of the reactants are converted into product B, while the remaining reactants presumably convert into product C. Yield can be influenced by many factors, including reaction time, temperature, kinetics, and the mechanism of the reaction.

The derivation of the yield for B using rate constants provides insight into the relationship between the rates of formation for B and C, and the resulting product distribution. Theoretical calculations of yield assume that all other conditions are constant and that the reaction proceeds with no side reactions or losses. If the calculated yield does not align with the experimental yield, it suggests possible experimental errors, alternative pathways, side reactions, or that some reactants may not be converting as expected.

Understanding chemical yield has significant practical applications, as it helps in optimizing chemical processes and scaling up reactions from the laboratory to industrial production. In research and industry, maximizing yield is often a primary objective to reduce costs and increase efficiency.

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Most popular questions from this chapter

The unimolecular decomposition of urea in aqueous solution is measured at two different temperatures, and the following data are observed: $$\begin{array}{ccc}\text { Trial Number } & \text { Temperature }\left(^{\circ} \mathbf{C}\right) & \boldsymbol{k}\left(\mathbf{s}^{-1}\right) \\\\\hline 1 & 60.0 & 1.20 \times 10^{-7} \\\2 & 71.5 & 4.40 \times 10^{-7}\end{array}$$ a. Determine the Arrhenius parameters for this reaction. b. Using these parameters, determine \(\Delta H^{\dagger}\) and \(\Delta S^{\frac{1}{3}}\) as described by the Eyring equation.

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Catalase is an enzyme that promotes the conversion of hydrogen peroxide \(\left(\mathrm{H}_{2} \mathrm{O}_{2}\right)\) into water and oxygen. The diffusion constant and radius for catalase are \(6.0 \times 10^{-7} \mathrm{cm}^{2} \mathrm{s}^{-1}\) and 51.2 A. For hydrogen peroxide the corresponding values are \(1.5 \times 10^{-5} \mathrm{cm}^{2} \mathrm{s}^{-1}\) and \(r \sim 2.0\) A. The experimentally determined rate constant for the conversion of hydrogen peroxide by catalase is \(5.0 \times 10^{6} \mathrm{M}^{-1} \mathrm{s}^{-1} .\) Is this a diffusioncontrolled reaction?

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