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You are performing an experiment using \(^{3} \mathrm{H}\) (halflife \(=4.5 \times 10^{3}\) days labeled phenylalanine in which the five aromatic hydrogens are labeled. To perform the experiment, the initial activity cannot be lower than \(10 \%\) of the initial activity when the sample was received. How long after receiving the sample can you wait before performing the experiment?

Short Answer

Expert verified
We can wait approximately 15,800 days or \(1.58 \times 10^4\) days before performing the experiment, while making sure the remaining activity is at least 10% of the initial activity.

Step by step solution

01

Write down the given information

Half-life \(T_{1/2} = 4.5 \times 10^3\) days We want to find the time before the remaining activity drops to 10% of the initial activity, i.e. \(A = 0.1 \times A_0\).
02

Determine the decay constant, \(\lambda\)

We can find \(\lambda\) using the given half-life and the formula: \(T_{1/2} = \frac{ln(2)}{\lambda}\) Rearrange the formula to find \(\lambda\): \(\lambda = \frac{ln(2)}{T_{1/2}}\) Now, substitute the given half-life: \(\lambda = \frac{ln(2)}{4.5 \times 10^3}\) Calculate the value of \(\lambda\): \(\lambda \approx 1.54 \times 10^{-4} \, \mathrm{day}^{-1}\)
03

Use the radioactive decay formula to find the time elapsed

We are given that the remaining 10% of the initial activity, so \(A = 0.1 \times A_0\). Now, use the radioactive decay formula: \(A = A_0 e^{-\lambda t}\) Substitute \(A = 0.1 \times A_0\) and the value of \(\lambda\): \(0.1 \times A_0 = A_0 e^{-(1.54 \times 10^{-4})t}\) Since we are looking for the time elapsed, divide both sides of the equation by \(A_0\) and take the natural logarithm of both sides: \(ln(0.1) = -(1.54 \times 10^{-4})t\) Rearrange to find \(t\): \(t = \frac{ln(0.1)}{-(1.54 \times 10^{-4})}\) Calculate the value of \(t\): \(t \approx 1.58 \times 10^4 \, \mathrm{days}\)
04

Report the answer

We can wait approximately 15,800 days or \(1.58 \times 10^4\) days before performing the experiment, while making sure the remaining activity is at least 10% of the initial activity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life Calculation
Understanding the concept of half-life is essential when studying radioactive decay, as it tells us how quickly a radioactive substance loses activity. The half-life, often represented as T1/2, is the time it takes for half of the radioactive atoms in a sample to decay. To calculate the half-life, you must consider the decay constant, λ, which is a measure of the probability for a single atom to decay per unit time.

In practice, if we know the half-life of a substance, we can determine how long it will take for any percentage of the initial amount to remain. For example, to calculate the time for the activity of a substance to fall to 10% of its original activity, we need to use the formula for exponential decay, alongside the known half-life or the decay constant. This connection allows scientists and researchers to plan experiments and safety measures around radioisotopes effectively.
Decay Constant
The decay constant, symbolized by λ, is crucial to predicting the behavior of a radioactive sample over time. Mathematically, it's inversely proportional to the half-life (T1/2) and can be calculated using the formula λ = ln(2) / T1/2, where ln is the natural logarithm function. This constant represents the fraction of atoms decaying per unit time, serving as a frequent factor in the equations governing radioactive decay.

How to Calculate Decay Constant from Half-Life

Given the half-life, we can find the decay constant with the natural logarithm of 2, approximately 0.693. Thus, a shorter half-life would mean a higher decay constant and a faster decay rate. This decay constant is imperative for accurately determining the elapsed time for a given level of decay, like losing down to 10% of initial radioactivity.
Natural Logarithm
The natural logarithm, denoted as ln, is a function that's intrinsically related to exponential growth and decay in nature. It is the inverse operation of taking 'e' (Euler's number, approximately 2.71828) to the power of a given number. Representing the time dimension in decay calculations, the natural logarithm is used to describe processes where change occurs continuously at a rate proportional to the current value.

When solving for unknown variables in radioactive decay, such as time or initial activity, the natural logarithm becomes essential. It translates the exponential equation into a linear form, making it possible to isolate and solve for the variable in question. For instance, to calculate the time until only 10% of a radioactive substance remains, we use the natural logarithm to handle the exponential nature of decay, enabling us to find a precise answer for the elapsed time.

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Most popular questions from this chapter

Bananas are somewhat radioactive due to the presence of substantial amounts of potassium. Potassium- 40 decays by two different paths: $$\begin{array}{l}_{19}^{40} \mathrm{K} \rightarrow_{20}^{40} \mathrm{Ca}+\beta^{-}(89.3 \%) \\ _{19}^{40} \mathrm{K} \rightarrow_{18}^{40} \mathrm{Ar}+\beta^{+}(10.7 \%)\end{array}$$ The half-life for potassium decay is \(1.3 \times 10^{9}\) years. Determine the rate constants for the individual channels.

P35.10 (Challenging) The first-order thermal decomposition of chlorocyclohexane is as follows: \(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{Cl}(g) \rightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{10}(g)+\mathrm{HCl}(g) .\) For a constant volume system the following total pressures were measured as a function of time: $$\begin{array}{rccr}\text { Time }(s) & P(\text { Torr }) & \text { Time }(s) & P(\text { Torr }) \\\\\hline 3 & 237.2 & 24 & 332.1 \\\6 & 255.3 & 27 & 341.1 \\\9 & 271.3 & 30 & 349.3 \\\12 & 285.8 & 33 & 356.9 \\\15 & 299.0 & 36 & 363.7 \\\18 & 311.2 & 39 & 369.9 \\\21 & 322.2 & 42 & 375.5\end{array}$$ a. Derive the following relationship for a first-order reaction: \\[P\left(t_{2}\right)-P\left(t_{1}\right)=\left(P\left(t_{\infty}\right)-P\left(t_{0}\right)\right) e^{-k t_{1}}\left(1e^{-k\left(t_{2}-t_{1}\right)}\right)\\] In this relation, \(P\left(t_{1}\right)\) and \(P\left(t_{2}\right)\) are the pressures at two specific times; \(\mathrm{P}\left(t_{0}\right)\) is the initial pressure when the reaction is initiated, \(P\left(t_{\infty}\right)\) is the pressure at the completion of the reaction, and \(k\) is the rate constant for the reaction. To derive this relationship do the following: i. Given the first-order dependence of the reaction, write the expression for the pressure of chlorocyclohexane at a specific time \(t_{1}\) ii. Write the expression for the pressure at another time \(t_{2},\) which is equal to \(t_{1}+\Delta\) where delta is a fixed quantity of time. iii. Write expressions for \(P\left(t_{\infty}\right)-P\left(t_{1}\right)\) and \(P\left(t_{\infty}\right) P\left(t_{2}\right)\) iv. Subtract the two expressions from part (iii). b. Using the natural log of the relationship from part (a) and the data provided in the table given earlier in this problem, determine the rate constant for the decomposition of chlorocyclohexane. (Hint: Transform the data in the table by defining \(t_{2}-t_{1}\) to be a constant value, for example, 9 s.

The gas-phase decomposition of ethyl bromide is a first-order reaction, occurring with a rate constant that demonstrates the following dependence on temperature: a. Determine the Arrhenius parameters for this reaction. b. Using these parameters, determine \(\Delta H^{\frac{t}{4}}\) and \(\Delta S^{\frac{2}{r}}\) as described by the Eyring equation.

Calculate the ratio of rate constants for two thermal reactions that have the same Arrhenius preexponential term but have activation energies that differ by \(1.0,10 .,\) and \(30 . \mathrm{kJ} / \mathrm{mol}\) for \(T=298 \mathrm{K}\).

Consider the following reaction involving bromophenol blue (BPB) and \(\mathrm{OH}^{-}: \mathrm{HBPB}(a q)+\mathrm{OH}^{-}(a q) \rightarrow\) \(\mathrm{BPB}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) .\) The concentration of \(\mathrm{BPB}\) can be monitored by following the absorption of this species and using the Beer-Lambert law. In this law, absorption \(A\) and concentration are linearly related. a. Express the reaction rate in terms of the change in absorbance as a function of time. b. Let \(A_{o}\) be the absorbance due to HBPB at the beginning of the reaction. Assuming that the reaction is first order with respect to both reactants, how is the absorbance of HBPB expected to change with time? c. Given your answer to part (b), what plot would you construct to determine the rate constant for the reaction?

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