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Imagine designing an experiment in which the presence of a gas is determined by simply listening to the gas with your ear. The human ear can detect pressures as low as \(2 \times 10^{-5} \mathrm{N} \mathrm{m}^{-2}\). Assuming that the eardrum has an area of roughly \(1 \mathrm{mm}^{2},\) what is the minimum collisional rate that can be detected by ear? Assume that the gas of interest is \(\mathrm{N}_{2}\) at \(298 \mathrm{K}\).

Short Answer

Expert verified
The minimum collisional rate that can be detected by ear is approximately \(1.04 \times 10^{-11}\) collisions per second. This is calculated by first finding the force detectable by the human ear, then using the ideal gas law to find the number of moles in the gas, and finally calculating the collisional rate using the formula: Collisional Rate = Pressure / (n × R × T).

Step by step solution

01

Calculate the Force

First, we need to find the force that the human ear can detect. Using the formula Pressure = Force/Area, we can rearrange to find the force: Force = Pressure × Area Given the pressure threshold is \(2 \times 10^{-5} \mathrm{N} \mathrm{m}^{-2}\), and the eardrum has an area of roughly \(1 \mathrm{mm}^{2}\), which is \(1 \times 10^{-6} \mathrm{m}^{2}\) in SI units. Force = \( (2 \times 10^{-5} \mathrm{N} \mathrm{m}^{-2}) (1 \times 10^{-6} \mathrm{m}^{2}) \) Force = \( 2 \times 10^{-11} \mathrm{N} \)
02

Calculate the Number of Moles Using Ideal Gas Law

We will now use the ideal gas law to find the number of moles (n) in the gas. This will help us determine the collisional rate. The ideal gas law is: PV = nRT Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (8.314 J/mol·K), and T is the temperature in Kelvin. It's given that the nitrogen gas (\(\mathrm{N}_2\)) is at a temperature of \(298 \mathrm{K}\). But we need to find the number of moles based on the minimum force detectable by the human ear. To do this, we should divide the force by the Avogadro's number (6.022 × 10²³ molecules/mol). Number of moles, n = Force / (Avogadro's number × mass of one nitrogen molecule) n = \( \dfrac{2 \times 10^{-11} \mathrm{N}}{(6.022 \times 10^{23} \text{ molecules/mol})(4.65 \times 10^{-26} \text{ kg)} \) n = \( \dfrac{2 \times 10^{-11} \mathrm{N}}{(6.022 \times 10^{23} \text{ molecules/mol})(4.65 \times 10^{-26} \text{ kg)} \) n ≈ 0.071 mol
03

Calculate the Collisional Rate

Now that we have the number of moles (n), we can calculate the collisional rate using the formula: Collisional Rate = Pressure / (n × R × T) Where P is the pressure, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Collisional Rate = \( \dfrac{2 \times 10^{-5} \mathrm{N} \mathrm{m}^{-2}}{(0.071 \text{ mol})(8.314 \text{ J/mol·K})(298 \text{ K})} \) Collisional Rate ≈ 1.04 × 10⁻¹¹ s⁻¹ So, the minimum collisional rate that can be detected by ear is approximately 1.04 × 10⁻¹¹ collisions per second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Gas Pressure Detection
Gas pressure detection plays a critical role in many scientific applications, including the experimental scenario where one listens to gas with the ear to detect its presence. At the foundation of this intriguing idea is the understanding that pressure is essentially the continuous physical force exerted on or against an object by something in contact with it—in this case, gas molecules.

This force per unit area can be perceived by the human eardrum as sound when the molecular collisions of the gas are frequent and strong enough. Our eardrums are sensitive membranes capable of detecting even minute pressures which can be translated into sound frequencies. This sensitivity threshold means that, under the right circumstances, one could indeed 'hear' the presence of a gas based on its collisional interactions with the eardrum.
The Ideal Gas Law in Action
The ideal gas law is a fundamental equation that relates the pressure, volume, temperature, and number of moles of an ideal gas. Traditionally represented as PV = nRT, the ideal gas law allows us to explore the behavior of gases and make pertinent calculations relevant to our daily lives and scientific endeavors.

In the context of our exercise, we apply this law to define the relationship between the detectable force on the eardrum, the pressure exerted by the gas, and subsequently, determine the number of moles of gas molecules responsible for this force. This application underscores the versatility of the ideal gas law and its central role in explaining the behavior of gases under various conditions.
Eardrum Sensitivity Threshold
The human ear is a remarkable organ, capable of detecting a remarkable range of sounds from the faintest whisper to the loudest roar. This ability is deeply connected to the sensitivity threshold of the eardrum. In the scientific scenario of using our hearing to detect gas presence, it translates to the human ear being able to pick up on the slightest changes in pressure, as delicate as 2 x 10^-5 N/m^2.

It's this incredible sensitivity that could, theoretically, allow us to detect the collision rate of nitrogen molecules within a gas at room temperature. When we talk about this threshold in terms of physics, we're essentially discussing the minimal amount of force required to create a sound wave that the eardrum can convert into an audible signal for our brains to process.
Utilizing Avogadro's Number
Avogadro's number, approximately 6.022 x 10^23, represents the number of units in one mole of a substance and is a key component in chemistry known for its use in converting between microscopic and macroscopic scales. Its utilization in the exercise is vital for calculating the number of nitrogen molecules exerting force on the eardrum, and subsequently, the moles of gas involved.

By including Avogadro's number in our calculations, we bridge the gap between observable physical phenomena, such as audible sound, and the molecular components responsible for them. It allows us not only to count the number of molecules but also to understand the direct impact of molecular collisions on our sensory experiences, such as hearing.

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Most popular questions from this chapter

(Challenging) Derive the Maxwell-Boltzmann distribution using the Boltzmann distribution introduced in statistical mechanics. Begin by developing the expression for the distribution in translational kinetic energy in one dimension and then extend it to three dimensions.

a. A standard rotary pump is capable of producing a vacuum on the order of \(10^{-3}\) Torr. What is the single-particle collisional frequency and mean free path for \(\mathrm{N}_{2}\) at this pressure and \(298 \mathrm{K} ?\) b. A cryogenic pump can produce a vacuum on the order of \(10^{-10}\) Torr. What is the collisional frequency and mean free path for \(\mathrm{N}_{2}\) at this pressure and \(298 \mathrm{K} ?\)

A comparison of \(\nu_{\text {ave}}, \nu_{m p},\) and \(\nu_{r m s}\) for the Maxwell speed distribution reveals that these three quantities are not equal. Is the same true for the one-dimensional velocity distributions?

A molecular beam apparatus employs supersonic jets that allow gas molecules to expand from a gas reservoir held at a specific temperature and pressure into a vacuum through a small orifice. Expansion of the gas results for achieving internal temperatures of roughly \(10 \mathrm{K} .\) The expansion can be treated as adiabatic, with the change in gas enthalpy accompanying expansion being converted to kinetic energy associated with the flow of the gas: \\[\Delta H=C_{P} T_{R}=\frac{1}{2} M \nu^{2}\\] The temperature of the reservoir \(\left(T_{R}\right)\) is generally greater than the final temperature of the gas, allowing one to consider the entire enthalpy of the gas to be converted into translational motion. a. For a monatomic gas \(C_{P}=5 / 2 R .\) Using this information, demonstrate that the final flow velocity of the molecular beam is related to the initial temperature of the reservoir \(\left(T_{R}\right)\) by \\[\nu=\sqrt{\frac{5 R T_{R}}{M}}\\] b. Using this expression, what is the flow velocity of a molecular beam of Ar where \(T_{R}=298 \mathrm{K} ?\) Notice that this is remarkably similar to the average speed of the gas. Therefore, the molecular beam resulting can be described as a gas that travels with velocity \(\nu\) but with a very low internal energy. In other words, the distribution of molecular speeds around the flow velocity is significantly reduced in this process.

You are a NASA engineer faced with the task of ensuring that the material on the hull of a spacecraft can withstand puncturing by space debris. The initial cabin air pressure in the craft of 1 atm can drop to 0.7 atm before the safety of the crew is jeopardized. The volume of the cabin is \(100 . \mathrm{m}^{3}\), and the temperature in the cabin is 285 K. Assuming it takes the space shuttle about 8 hours from entry into orbit until landing, what is the largest circular aperture created by a hull puncture that can be safely tolerated assuming that the flow of gas out of the spaceship is effusive? Can the escaping gas from the spaceship be considered as an effusive process? (You can assume that the air is adequately represented by \(\mathrm{N}_{2}\).

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