Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Problem numbers in red indicate that the solution to the problem is given in the Student's Solutions Manual.a. What is the possible number of microstates associated with tossing a coin \(N\) times and having it come up \(H\) times heads and \(T\) times tails? b. For a series of 1000 tosses, what is the total number of microstates associated with \(50 \%\) heads and \(50 \%\) tails? c. How much less probable is the outcome that the coin will land \(40 \%\) heads and \(60 \%\) tails?

Short Answer

Expert verified
a. The number of microstates associated with tossing a coin N times and having it come up H times heads and T times tails can be calculated using the Combination formula: \( \binom{N}{H} = \frac{N!}{H!(N-H)!} \). b. For a series of 1000 tosses with 50% heads and 50% tails, the total number of microstates is \( \binom{1000}{500} = \frac{1000!}{500!500!} \). c. The probability of 40% heads and 60% tails compared to 50% heads and 50% tails can be calculated by comparing the combinations: \( \frac{\binom{1000}{400}}{\binom{1000}{500}} \). Calculate the numerical values to find out how much less probable this outcome is.

Step by step solution

01

a. Calculate the number of microstates associated with an N-times coin toss

To find the number of possible microstates when tossing a coin N times and getting H times heads and T times tails, we will use the Combination formula as follows: \[ \binom{N}{H} = \frac{N!}{H!(N - H)!} \] Here, N represents the total number of tosses, and H represents the number of heads. Since we know that H + T = N, the position of tails is already determined by the number of heads, so there is no need to consider T in the formula.
02

b. Number of microstates associated with 50% heads and 50% tails in 1000 tosses

Given 1000 tosses, 50% heads and 50% tails mean 500 heads and 500 tails. We'll calculate the combination using the total number of tosses (N = 1000) and the number of heads (H = 500): \[ \binom{1000}{500} = \frac{1000!}{500!500!} \] To find the numerical result, a calculator or computer program can be used.
03

c. The probability of 40% heads and 60% tails compared to 50% heads and 50% tails

We will calculate the probabilities for 40% heads and 60% tails and compare it to the probability found in part b. For 40% heads and 60% tails, we will have 400 heads and 600 tails. Using the combination: \[ \binom{1000}{400} = \frac{1000!}{400!600!} \] Now, we need to compare the probabilities: \[ \frac{\binom{1000}{400}}{\binom{1000}{500}} \] By calculating the numerical values using a calculator and/or a computer program, you can find out how much less probable the outcome of 40% heads and 60% tails is compared to the 50% heads and 50% tails scenario.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Combination Formula
The combination formula is a crucial tool in probability, especially in problems involving the arrangement of items like in a coin toss experiment. It is expressed as:
\[\binom{N}{H} = \frac{N!}{H!(N - H)!}\] Here, \(N\) represents the total number of trials or events, while \(H\) represents the specific outcomes you are interested in, such as the number of heads in a series of coin tosses.
  • \(N!\) ("N factorial") is the product of all positive integers up to \(N\).
  • \(H!\) and \((N-H)!\) are similar factorials for heads and tails, respectively.
This formula helps determine the number of ways to choose a specific number of successes (\(H\) heads) from \(N\) trials. Don’t worry about calculating it by hand; factorials grow rapidly, and often a calculator or a computer program is used for practical computation.
Calculating Probability
Probability is all about finding out how likely an event is to happen. Mathematically, it is the number of favorable outcomes divided by the total number of possible outcomes. For instance, if you want to know the probability of getting a certain number of heads in a coin toss series, you determine:
\[P = \frac{\text{Number of favorable microstates}}{\text{Total number of microstates}}\] In step c of the exercise, you see this applied to compare the probability of an experiment resulting in 40% heads and 60% tails to 50% heads and 50% tails. This involves finding the number of microstates for each scenario and using these to calculate the probabilities and their ratio.
This gives a direct comparison, showing how much less likely one outcome is compared to another.
Understanding these concepts helps to simplify solving probability-based problems and makes predicting outcomes more intuitive.
Exploring the Coin Toss Experiment
A coin toss experiment is a classic example used in probability and statistics to understand random processes. When tossing a coin multiple times, every toss can result in either heads or tails, and each result has a probability of \(0.5\) if the coin is fair.
The beauty of this experiment is in the predictable nature of large numbers. As you increase the number of tosses, you can apply formulas like combinations to find the number of microstates associated with specific outcomes, like how often half the tosses are heads.
When we deal with a large number of tosses, like 1000, calculating the exact number of each outcome using the combination formula helps you visualize how varied the results can be. This experiment illustrates fundamental principles of probability and showcases the predictable yet random nature of such processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hydroxyl radicals are of interest in atmospheric processes due to their oxidative ability, Determine the partition function for the vibrational degrees of freedom for OH \(\left(\tilde{\nu}=3735 \mathrm{cm}^{-1}\right)\) and calculate the probability of occupying the first excited vibrational level at \(260 .\) K. Would you expect the probability for occupying the first-excited vibrational level for \(\mathrm{OD}\left(\widetilde{\nu}=2721 \mathrm{cm}^{-1}\right)\) to be greater or less than for OH?

The probability of occupying a given excited state \(p_{i}\) is given by \(p_{i}=n_{i} / N=e^{-\beta \kappa_{i}} / q,\) where \(n_{i}\) is the occupation number for the state of interest, \(N\) is the number of particles, and \(\varepsilon_{i}\) is the energy of the level of interest. Demonstrate that the preceding expression is independent of the definition of energy for the lowest state.

When determining the partition function for the harmonic oscillator, the zero- point energy of the oscillator was ignored. Show that the expression for the probability of occupying a specific energy level of the harmonic oscillator with the inclusion of zero-point energy is identical to that ignoring zero- point energy.

Consider the case of 10 oscillators and 8 quanta of energy. Determine the dominant configuration of energy for this system by identifying energy configurations and calculating the corresponding weights. What is the probability of observing the dominant configuration?

For a set of nondegenerate levels with energy \(\varepsilon / k=0,100 .,\) and \(200 .\) K, calculate the probability of occupying each state when \(T=50 ., 500 .,\) and \(5000 .\) K. As the temperature continues to increase, the probabilities will reach a limiting value. What is this limiting value?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free