Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

VSEPR (valence state electron pair repulsion) theory was formulated to anticipate the local geometry about an atom in a molecule (see discussion in Section 25.1). All that is required is the number of electron pairs surrounding the atom, broken down into bonded pairs and nonbonded (lone) pairs. For example, the carbon in carbon tetrafluoride is surrounded by four electron pairs, all of them tied up in \(\mathrm{CF}\) bonds, whereas the sulfur in sulfur tetrafluoride is surrounded by five electron pairs, four of which are tied up in SF bonds with the fifth being a lone pair. VSEPR theory is based on two simple rules. The first is that electron pairs (either lone pairs or bonds) will seek to avoid each other as much as possible. Thus, two electron pairs will lead to a linear geometry, three pairs to a trigonal planar geometry, four pairs to a tetrahedral geometry, five pairs to a trigonal bipyramidal geometry, and six pairs to an octahedral geometry. Although this knowledge is sufficient to assign a geometry for a molecule such as carbon tetrafluoride (tetrahedral), it is not sufficient to specify the geometry of a molecule such as sulfur tetrafluoride. Does the lone pair assume an equatorial position on the trigonal bipyramid leading to a seesaw geometry, or an axial position leading to a trigonal pyramidal geometry? The second rule, that lone pairs take up more space than bonds, clarifies the situation. The seesaw geometry in which the lone pair is \(90^{\circ}\) to two of the SF bonds and \(120^{\circ}\) to the other two bonds is preferable to the trigonal pyramidal geometry in which three bonds are \(90^{\circ}\) to the lone pair. Although VSEPR theory is easy to apply, its results are strictly qualitative and often of limited value. For example, although the model tells us that sulfur tetrafluoride adopts a seesaw geometry, it does not reveal whether the trigonal pyramidal structure (or any other structure) is an energy minimum, and if it is, what its energy is relative to the seesaw form. Also it has little to say when more than six electron pairs are present. For example, VSEPR theory tells us that xenon hexafluoride is not octahedral, but it does not tell us what geometry the molecule actually assumes. Hartree-Fock molecular orbital calculations provide an alternative. a. Optimize the structure of \(\mathrm{SF}_{4}\) in a seesaw geometry \(\left(C_{2 v} \text { symmetry }\right)\) using the HF/3-21G model and calculate vibrational frequencies (the infrared spectrum). This calculation is necessary to verify that the energy is at a minimum. Next, optimize the geometry of \(\mathrm{SF}_{4}\) in a trigonal pyramidal geometry and calculate its vibrational frequencies. Is the seesaw structure an energy minimum? What leads you to your conclusion? Is it lower in energy than the corresponding trigonal pyramidal structure in accordance with VSEPR theory? What is the energy difference between the two forms? Is it small enough that both might actually be observed at room temperature? Is the trigonal pyramidal structure an energy minimum? b. Optimize the geometry of \(\mathrm{XeF}_{6}\) in an octahedral geometry \(\left(\mathrm{O}_{\mathrm{h}} \text { symmetry }\right)\) using the HF/3-21G model and calculate vibrational frequencies. Next, optimize \(\mathrm{XeF}_{6}\) in a geometry that is distorted from octahedral (preferably a geometry with \(\left.C_{1} \text { symmetry }\right)\) and calculate its vibrational frequencies. Is the octahedral form of \(\mathrm{XeF}_{6}\) an energy minimum? What leads you to your conclusion? Does distortion lead to a stable structure of lower energy?

Short Answer

Expert verified
To solve this problem, first optimize the structures of SF₄ and XeF₆ in their different geometries using the Hartree-Fock model and the 3-21G basis set. Next, calculate the vibrational frequencies for these optimized structures. Analyze the energies and vibrational frequencies to determine the energy minimum for each molecule and compare the results with the predictions from VSEPR theory. For SF₄, check if the seesaw structure has lower energy than the trigonal pyramidal structure, and for XeF₆, examine if the octahedral form is an energy minimum or if distortion leads to a more stable structure.

Step by step solution

01

Optimize the structures

Using appropriate software that can handle Hartree-Fock calculations, optimize the structures for each of the given molecules and their geometries. - For SF4: optimize in seesaw (C2v symmetry) and trigonal pyramidal geometries. - For XeF6: optimize in octahedral (Oh symmetry) and distorted octahedral geometries.
02

Calculate vibrational frequencies

Calculate vibrational frequencies for the optimized structures of SF4 and XeF6.
03

Analyze the results

Analyze the energies and vibrational frequencies of the optimized structures to answer the following questions: - For SF4: - Is the seesaw structure an energy minimum? (Look for the structure with the lowest energy) - Is the seesaw structure lower in energy than the trigonal pyramidal structure, as VSEPR theory suggests? - Calculate the energy difference between the two structures. - Is the energy difference small enough to observe both structures at room temperature? - Is the trigonal pyramidal structure an energy minimum? - For XeF6: - Is the octahedral structure an energy minimum? - Does distortion lead to a more stable structure of lower energy? Remember that the results provided by the Hartree-Fock model are only qualitative and they should be compared with VSEPR theory predictions to draw conclusions about the stability and relative energies of the different molecular geometries.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry Optimization
The process of molecular geometry optimization is akin to finding the most comfortable position for a group of people on a sofa; each individual tries to find a spot where they have the most personal space. Similarly, atoms within a molecule adjust their positions to minimize repulsive forces and maximize stability, resulting in the most energetically favorable arrangement.

Using computational methods, such as the Hartree-Fock calculations mentioned in the exercise, scientists can simulate this 'comfort-seeking' behavior by adjusting atomic positions and calculating the energy at each step. Optimization continues until the lowest possible energy configuration is achieved, which is considered an energy minimum. If further adjustments increase the energy, the structure is said to have reached its optimal geometry.

Applying VSEPR Theory and Hartree-Fock Calculations

Using the example of sulfur tetrafluoride (\textsf{SF}\(_4\)), VSEPR theory predicts a seesaw geometry based on the electron pair repulsion. However, to confirm this shape is the energy minimum, calculations using the Hartree-Fock method are necessary. When a molecule like \textsf{XeF}\(_6\) defies simple VSEPR predictions, more advanced methods like Hartree-Fock are particularly useful in exploring potential geometries and finding the conformation with the lowest energy, whether it be octahedral or a distorted shape.
Hartree-Fock Molecular Orbital Calculations
Imagine trying to solve a jigsaw puzzle where each piece represents the behavior of an electron in a molecule. Hartree-Fock molecular orbital calculations are similar to this task; they attempt to describe the positions and energies of electrons within molecules. This quantum chemistry approach considers electrons to move independently in an average field created by all other electrons.

The calculations are based on a set of mathematical equations called the Hartree-Fock equations, which must be solved iteratively to find the distribution of electrons that minimizes the energy of the molecule. This approach generates a molecular orbital diagram depicting the energy levels and occupancy of the electrons.

Connecting Theory and Computational Models

In the context of the exercise, after performing Hartree-Fock calculations for the \textsf{SF}\(_4\) and \textsf{XeF}\(_6\) molecules, the optimized geometries can be compared to the predictions made by VSEPR theory to evaluate their accuracy and gain insights into the molecular shapes that could not be explained by VSEPR alone. Complementing qualitative models with quantitative calculations allows us to verify which molecular geometries are true energy minima.
Vibrational Frequency Analysis
Vibrational frequency analysis is a technique that could be likened to playing various music notes by stretching guitar strings. Each vibrational mode of a molecule is a 'note' that depends on the shape and mass of the molecule, much like the sound depends on the length and tension of the guitar string.

This type of analysis provides information about the stability of a molecule and the nature of its chemical bonds. By calculating the vibrational frequencies, chemists can determine if a predicted structure corresponds to an energy minimum. Frequencies corresponding to real vibrations (positive values) indicate a stable structure, whereas imaginary frequencies (negative values or written with an 'i') suggest that the structure is not at an energy minimum and is, therefore, unstable.

Practical Implications for \textsf{SF}\(_4\) and \textsf{XeF}\(_6\)

Applying vibrational frequency analysis to \textsf{SF}\(_4\) and \textsf{XeF}\(_6\), as outlined in the exercise, helps confirm whether the seesaw and distorted octahedral geometries, respectively, are stable. It checks if the molecules in these conformations would vibrate naturally without leading to a structural change, which is critical for validating both the VSEPR theory and the results from Hartree-Fock calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Diels-Alder reactions commonly involve electronrich dienes and electron- deficient dienophiles: The rate of these reactions generally increases with the \(\pi\) -donor ability of the diene substituent, \(Y\), and with the \(\pi\) -acceptor ability of the dienophile substituent, \(\mathrm{X}\) The usual interpretation is that electron donors will push up the energy of the HOMO on the diene and that electron acceptors will push down the energy of the LUMO on the dienophile: The resulting decrease in the HOMO-LUMO gap leads to a stronger interaction between diene and dienophile and to a decrease in the activation barrier. a. Obtain equilibrium geometries for acrylonitrile, 1,1 dicyanoethylene, \(c i s-\) and \(t r a n s-1,2-\) dicyanoethylene tricyanoethylene, and tetracyanoethylene using the HF/3-21G model. Plot the LUMO energy for each dienophile versus the \(\log\) of the observed relative rate for its addition to cyclopentadiene (listed below the structures in the preceding figure). Is there a reasonable correlation between LUMO energy and relative rate? b. Obtain transition-state geometries for Diels-Alder cycloadditions of acrylonitrile and cyclopentadiene and tetracyanoethylene and cyclopentadiene using the HF/3-21G model. Also obtain a geometry for cyclopentadiene. Calculate activation energies for the two reactions. How does the calculated difference in activation energies compare with the experimental difference (based on a value of 7.61 for the difference in the log of the rates and assuming \(298 \mathrm{K}) ?\)

singlet and triplet carbenes exhibit different properties and show markedly different chemistry. For example, a singlet carbene will add to a cis- disubstituted alkene to produce only \(c i s\) -disubstituted cyclopropane products (and to a trans-disubstituted alkene to produce only trans- disubstituted cyclopropane products), whereas a triplet carbene will add to produce a mixture of cis and trans products. The origin of the difference lies in the fact that triplet carbenes are biradicals (or diradicals) and exhibit chemistry similar to that exhibited by radicals, whereas singlet carbenes incorporate both a nucleophilic site (a low-energy unfilled molecular orbital) and an electrophilic site (a high- energy filled molecular orbital); for example, for singlet and triplet methylene: It should be possible to take advantage of what we know about stabilizing radical centers versus stabilizing empty orbitals and use that knowledge to design carbenes that will either be singlets or triplets. Additionally, it should be possible to say with confidence that a specific carbene of interest will either be a singlet or a triplet and, thus, to anticipate its chemistry. The first step is to pick a model and then to establish the error in the calculated singlet-triplet energy separation in methylene where the triplet is known experimentally to be approximately \(42 \mathrm{kJ} / \mathrm{mol}\) lower in energy than the singlet. This can then be applied as a correction for calculated singlet-triplet separations in other systems. a. Optimize the structures of both the singlet and triplet states of methylene using both Hartree-Fock and B3LYP density functional models with the \(6-31 G^{*}\) basis set. Which state (singlet or triplet) is found to be of lower energy according to the HF/6-31G* calculations? Is the singlet or the triplet unduly favored at this level of calculation? Rationalize your result. (Hint: Triplet methylene contains one fewer electron pair than singlet methylene.) What energy correction needs to be applied to calculated singlet-triplet energy separations? Which state (singlet or triplet) is found to be of lower energy according to the B3LYP/6-31G" calculations? What energy correction needs to be applied to calculated energy separations? b. Proceed with either the HF/6-31G* or B3LYP/6-31G* model, depending on which leads to better agreement for the singlet-triplet energy separation in methylene. Optimize singlet and triplet states for cyanomethylene, methoxymethylene, and cyclopentadienylidene: Apply the correction obtained in the previous step to estimate the singlet-triplet energy separation in each. For each of the three carbenes, assign the ground state as singlet or triplet. Relative to hydrogen (in methylene), has the cyano substituent in cyanomethylene and the methoxy substituent in methoxymethylene led to favoring of the singlet or the triplet? Rationalize your result by first characterizing cyano and methoxy substituents as \(\pi\) donors or \(\pi\) acceptors, and then speculating about how a donor or acceptor would stabilize or destabilize singlet and triplet methylene. Has incorporation into a cyclopentadienyl ring led to increased preference for a singlet or triplet ground state (relative to the preference in methylene)? Rationalize your result. (Hint: Count the number of \(\pi\) electrons associated with the rings in both singlet and triplet states.)

Lithium provides a very simple example of the effect of oxidation state on overall size. Perform HF/6-31G* calculations on lithium cation, lithium atom, and lithium anion, and compare the three electron density surfaces corresponding to enclosure of \(99 \%\) of the total electron density. Which is smallest? Which is largest? How does the size of lithium relate to the number of electrons? Which surface most closely resembles a conventional space-filling model? What, if anything does this tell you about the kinds of molecules that were used to establish the space-filling radius for lithium?

Ammonia provides a particularly simple example of the dependence of vibrational frequencies on the atomic masses and of the use of vibrational frequencies to distinguish between a stable molecule and a transition state. First examine the vibrational spectrum of pyramidal ammonia ("ammonia" on the precalculated Spartan file). a. How many vibrational frequencies are there? How does this number relate to the number of atoms? Are all fre- quencies real numbers or are one or more imaginary numbers? Describe the motion associated with each frequency and characterize each as being primarily bond stretching, angle bending, or a combination of the two. Is bond stretching or angle bending easier? Do the stretching motions each involve a single \(\mathrm{NH}\) bond or do they involve combinations of two or three bonds? b. Next, consider changes to the vibrational frequencies of ammonia as a result of substituting deuteriums for hydrogens ("perdeuteroammonia" on the precalculated Spartan file \() .\) Are the frequencies in \(\mathrm{ND}_{3}\) larger, smaller, or unchanged from those in \(\mathrm{NH}_{3}\) ? Are any changes greater for motions that are primarily bond stretching or motions that are primarily angle bending? c. Finally, examine the vibrational spectrum of an ammonia molecule that has been constrained to a planar geometry ("planar ammonia"' on the Spartan download). Are all the frequencies real numbers? If not, describe the motions associated with any imaginary frequencies and relate them to the corresponding motion(s) in the pyramidal equilibrium form.

Pyramidal inversion in the cyclic amine aziridine is significantly more difficult than inversion in an acyclic amine, for example, requiring \(80 \mathrm{kJ} / \mathrm{mol}\) versus \(23 \mathrm{kJ} / \mathrm{mol}\) in dimethylamine according to HF/6-31G* calculations. One plausible explanation is that the transition state for inversion needs to incorporate a planar trigonal nitrogen center, which is obviously more difficult to achieve in aziridine, where one bond angle is constrained to a value of around \(60^{\circ},\) than it is in dimethylamine. Such an interpretation suggests that the barriers to inversion in the corresponding four- and fivemembered ring amines (azetidine and pyrrolidine) should also be larger than normal and that the inversion barrier in the six-membered ring amine (piperidine) should be quite close to that for the acyclic. Optimize the geometries of aziridine, azetidine, pyrrolidine, and piperidine using the HF/6-31G* model. Starting from these optimized structures, provide guesses at the respective inversion transition states by replacing the tetrahedral nitrogen center with a trigonal center. Obtain transition states using the same Hartree-Fock model and calculate inversion barriers. Calculate vibrational frequencies to verify that you have actually located the appropriate inversion transition states. Do the calculated inversion barriers follow the order suggested in the preceding figure? If not, which molecule(s) appear to be anomalous? Rationalize your observations by considering other changes in geometry from the amine to the transition state.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free