Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Lithium provides a very simple example of the effect of oxidation state on overall size. Perform HF/6-31G* calculations on lithium cation, lithium atom, and lithium anion, and compare the three electron density surfaces corresponding to enclosure of \(99 \%\) of the total electron density. Which is smallest? Which is largest? How does the size of lithium relate to the number of electrons? Which surface most closely resembles a conventional space-filling model? What, if anything does this tell you about the kinds of molecules that were used to establish the space-filling radius for lithium?

Short Answer

Expert verified
The HF/6-31G* calculations on lithium cation (Li+), lithium atom (Li), and lithium anion (Li-) result in three electron density surfaces corresponding to the enclosure of 99% of the total electron density. It is observed that as the oxidation state of lithium increases, the size of the surface decreases, while the opposite occurs when the oxidation state decreases due to changes in electron-electron repulsions. Among the three surfaces, the lithium atom (Li) electron density surface most closely resembles a conventional space-filling model, which represents the van der Waals radius of the atom. This analysis indicates that the space-filling radius for lithium may have been established based on molecules containing lithium in its neutral oxidation state.

Step by step solution

01

1. Perform HF/6-31G* calculations

Start by performing the Hartree-Fock calculations using the 6-31G* basis set for Li+, Li, and Li-. You can do this using software such as Gaussian, ORCA, or any other computational chemistry software.
02

2. Compare electron density surfaces

Once you have the results from your calculations, generate the electron density surfaces for Li+, Li, and Li- at the 99% total electron density level. Compare the size of these surfaces to determine which one is smallest and which one is largest.
03

3. Analyze the size of lithium and its relationship with the number of electrons

Analyze the results to see how the size of the electron density surfaces (hence the size of lithium species) is related to the number of electrons. Generally, as the oxidation state increases (loses electrons), the size decreases due to the reduction of electron-electron repulsions. On the other hand, as the oxidation state decreases (gains electrons), the size increases due to the increase in electron-electron repulsions.
04

4. Determine which surface most closely resembles a conventional space-filling model

Identify which electron density surface best resembles a conventional space-filling model out of the three surfaces generated for Li+, Li, and Li-. The space-filling model generally represents the van der Waals radius of the atom or ion.
05

5. Draw conclusions regarding the molecules responsible for the space-filling radius of lithium

Based on your comparison of the electron density surfaces and identification of which surface resembles a conventional space-filling model, infer what kinds of molecules may have been used to establish the space-filling radius for lithium. Consider the oxidation states of lithium in those molecules and the role they play in determining the size of lithium species.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lithium Cation
Lithium cation, often denoted as Li+, is a lithium atom that has lost an electron. This loss of an electron gives the cation a positive charge.

Due to the absence of an electron, the electron-electron repulsions that usually result in a larger atomic radius are reduced. This makes a cation smaller than its corresponding neutral atom.
  • The HF/6-31G* calculation for Li+ involves computing its electron density surface and understanding its impact on the size and charge distribution.
  • It is important to note that Li+, being smaller due to its positive charge, binds more effectively with negatively charged species compared to its neutral counterpart.
Understanding the nature of Li+ is crucial for interpreting how various oxidation states affect the physical properties of lithium, particularly its size.
Electron Density Surfaces
Electron density surfaces represent the distribution of electrons around an atom within a molecule. In chemistry, these surfaces help visualize the spatial regions with high probability of finding electrons.

For lithium species, electron density calculations are performed at 99% of the total electron density to best approximate atomic size.
  • These surfaces allow scientists to understand atomic interactions and reactivity, essential for molecular modeling and drug design.
  • In lithium cation (Li+), lithium atom (Li), and lithium anion (Li-), electron density surfaces show clear differences in size and shape.
The comparison of various electron density surfaces, therefore, offers insight into phenomena such as atomic and molecular stability as well as reactivity.
Oxidation State
The oxidation state in chemistry refers to the degree of oxidation of an atom within a substance.

It’s crucial in predicting the chemical behavior of an element, including lithium, as seen in various oxidation states:
  • As electrons are added or removed, the oxidation state changes, impacting the molecular geometry and electron density surfaces.
  • Higher oxidation states (e.g., Li+) result in fewer electrons, leading to reduced repulsive forces and, thus, smaller atomic size.
  • Conversely, a lower oxidation state (e.g., Li-) means more electrons, increasing repulsion and atomic size.
By analyzing these relationships, chemists can predict how changes in oxidation state will affect molecular interactions and properties.
Space-Filling Model
The space-filling model is a way to represent molecules, emphasizing the relative sizes of atoms and their spatial arrangement.

This model shows atoms as spheres whose radii are proportional to their van der Waals radii, offering an intuitive visualization of their real 3D form.
  • In lithium species, space-filling models can closely resemble the most accurate electron density surface. This is crucial for correctly representing molecular shape and electronic environment.
  • The model provides clarity on how atoms within a molecule pack and interact with one another, significantly influencing their chemical properties and stability.
Understanding which electron density surface of lithium resembles this configuration aids in identifying the most suitable representation based on electron configurations and atomic size.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For many years, a controversy raged concerning the structures of so-called "electron-deficient" molecules, that is, molecules with insufficient electrons to make normal two-atom, two- electron bonds. Typical is ethyl cation, \(\mathrm{C}_{2} \mathrm{H}_{5}^{+}\) formed from protonation of ethene. Is it best represented as an open Lewis structure with a full positive charge on one of the carbons, or as a hydrogenbridged structure in which the charge is dispersed onto several atoms? Build both open and hydrogen-bridged structures for ethyl cation. Optimize the geometry of each using the B3LYP/6-31G* model and calculate vibrational frequencies. Which structure is lower in energy, the open or hydrogenbridged structure? Is the higher energy structure an energy minimum? Explain your answer.

Aromatic molecules such as benzene typically undergo substitution when reacted with an electrophile such as \(\mathrm{Br}_{2},\) whereas alkenes such as cyclohexene most commonly undergo addition: What is the reason for the change in preferred reaction in moving from the alkene to the arene? Use the Hartree- Fock \(6-31 G^{*}\) model to obtain equilibrium geometries and energies for reactants and products of both addition and substitution reactions of both cyclohexene and benzene (four reactions in total). Assume trans addition products (1,2-dibromocyclohexane and 5,6-dibromo-1,3-cyclohexadiene). Is your result consistent with what is actually observed? Are all four reactions exothermic? If one or more are not exothermic, provide a rationale as to why.

It is well known that cyanide acts as a "carbon" and not a "nitrogen" nucleophile in \(\mathrm{S}_{\mathrm{N}} 2\) reactions, for example, How can this behavior be rationalized with the notion that nitrogen is in fact more electronegative than carbon and, therefore, would be expected to hold any excess electrons? a. Optimize the geometry of cyanide using the HF/3-21G model and examine the HOMO. Describe the shape of the HOMO of cyanide. Is it more concentrated on carbon or nitrogen? Does it support the picture of cyanide acting as a carbon nucleophile? If so, explain why your result is not at odds with the relative electronegativities of carbon and nitrogen. Why does iodide leave following nucleophilic attack by cyanide on methyl iodide? b. Optimize the geometry of methyl iodide using the HF/3-21G model and examine the LUMO. Describe the shape of the LUMO of methyl iodide. Does it anticipate the loss of iodide following attack by cyanide? Explain.

Pyramidal inversion in the cyclic amine aziridine is significantly more difficult than inversion in an acyclic amine, for example, requiring \(80 \mathrm{kJ} / \mathrm{mol}\) versus \(23 \mathrm{kJ} / \mathrm{mol}\) in dimethylamine according to HF/6-31G* calculations. One plausible explanation is that the transition state for inversion needs to incorporate a planar trigonal nitrogen center, which is obviously more difficult to achieve in aziridine, where one bond angle is constrained to a value of around \(60^{\circ},\) than it is in dimethylamine. Such an interpretation suggests that the barriers to inversion in the corresponding four- and fivemembered ring amines (azetidine and pyrrolidine) should also be larger than normal and that the inversion barrier in the six-membered ring amine (piperidine) should be quite close to that for the acyclic. Optimize the geometries of aziridine, azetidine, pyrrolidine, and piperidine using the HF/6-31G* model. Starting from these optimized structures, provide guesses at the respective inversion transition states by replacing the tetrahedral nitrogen center with a trigonal center. Obtain transition states using the same Hartree-Fock model and calculate inversion barriers. Calculate vibrational frequencies to verify that you have actually located the appropriate inversion transition states. Do the calculated inversion barriers follow the order suggested in the preceding figure? If not, which molecule(s) appear to be anomalous? Rationalize your observations by considering other changes in geometry from the amine to the transition state.

Chemists know that nitric and sulfuric acids are strong acids and that acetic acid is a weak acid. They would also agree that ethanol is at best a very weak acid. Acid strength is given directly by the energetics of deprotonation (heterolytic bond dissociation); for example, for acetic acid: \\[ \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} \longrightarrow \mathrm{CH}_{3} \mathrm{CO}_{2}^{-}+\mathrm{H}^{+} \\] As written, this is a highly endothermic process, because not only is a bond broken but two charged molecules are created from the neutral acid. It occurs readily in solution only because the solvent acts to disperse charge. Acid strength can be calculated simply as the difference in energy between the acid and its conjugate base (the energy of the proton is 0 ). In fact, acid strength comparisons among closely related systems, for example, carboxylic acids, are quite well described with practical quantum chemical models. This is consistent with the ability of the same models to correctly account for relative base strengths (see discussion in Section \(26.8 .3)\) Another possible measure of acid strength is the degree of positive charge on the acidic hydrogen as measured by the electrostatic potential. It is reasonable to expect that the more positive the potential in the vicinity of the hydrogen, the more easily it will dissociate and the stronger the acid. This kind of measure, were it to prove successful, offers an advantage over the calculation of reaction energy, in that only the acid (and not the conjugate base ) needs to be considered. a. Obtain equilibrium geometries for nitric acid, sulfuric acid, acetic acid, and ethanol using the HF/3-21G model, and compare electrostatic potential maps. Be certain to choose the same (color) scale for the four acids. For which acid is the electrostatic potential in the vicinity of (the acidic) hydrogen most positive? For which is it least positive? Do electrostatic potential maps provide a qualitatively correct account of the relative acid strength of these four compounds? b. Obtain equilibrium geometries for several of the carboxylic acids found in the following table using the HF/3-21G model and display an electrostatic potential map for each. "Measure" the most positive value of the electrostatic potential associated with the acidic hydrogen in each of these compounds and plot this against experimental \(\mathrm{p} K_{\mathrm{a}}\) (given in the preceding table). Is there a reasonable correlation between acid strengths and electrostatic potential at hydrogen in this closely related series of acids?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free