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Is the superposition wave function \(\psi(x)=\sqrt{2 / a}[\sin (n \pi x / a)+\sin (m \pi x / a)]\) an eigenfunction of the total energy operator for the particle in the box?

Short Answer

Expert verified
The given superposition wave function \(\psi(x) = \sqrt{2 / a}[\sin (n \pi x / a)+\sin (m \pi x / a)]\) is not an eigenfunction of the total energy operator for the particle in the box. This is because when the total energy operator acts on ψ(x), the resulting expression does not have the form Eψ(x).

Step by step solution

01

Recall the total energy operator and the eigenfunction equation for a particle in a box

For a particle in a box, the total energy operator (Hamiltonian) is given by: \[H = -\frac{\hbar^2}{2m} \frac{d^2}{dx^2} \] An eigenfunction ψ(x) satisfies the following equation: \[H \psi(x) = E \psi(x)\]
02

Apply the total energy operator on the given wave function

Now let's apply the total energy operator H on the given superposition wave function ψ(x): \(H \psi(x) = -\frac{\hbar^2}{2m} \frac{d^2}{dx^2} \left[ \sqrt{\frac{2}{a}} \left(\sin \left(\frac{n \pi x}{a}\right) + \sin \left(\frac{m \pi x}{a}\right)\right) \right]\)
03

Calculate the second derivative

To compute Hψ(x), we need to find the second derivative with respect to x: \(\frac{d^2}{dx^2} \left[ \sqrt{\frac{2}{a}} \left(\sin \left(\frac{n \pi x}{a}\right) + \sin \left(\frac{m \pi x}{a}\right)\right) \right] \) Taking the second derivative, we get: \(\frac{d^2}{dx^2} \psi(x) = \frac{2}{a} \left(-\frac{n^2 \pi^2}{a^2}\sin\left(\frac{n \pi x}{a}\right) - \frac{m^2 \pi^2}{a^2}\sin\left(\frac{m \pi x}{a}\right)\right)\)
04

Verify if it satisfies the eigenfunction equation

Now, we can apply the total energy operator on the given wave function: \(H \psi(x) = -\frac{\hbar^2}{2m} \left(\frac{2}{a} \left(-\frac{n^2 \pi^2}{a^2}\sin\left(\frac{n \pi x}{a}\right) - \frac{m^2 \pi^2}{a^2}\sin\left(\frac{m \pi x}{a}\right)\right) \right)\) Simplify the expression: \(H \psi(x) = \frac{\hbar^2}{ma^2} \left(n^2 \pi^2 \sin\left(\frac{n \pi x}{a}\right) + m^2 \pi^2 \sin\left(\frac{m \pi x}{a}\right) \right)\) We see that the resulting expression, when the total energy operator acts on ψ(x), does not have the form Eψ(x). This implies that the given superposition wave function ψ(x) is not an eigenfunction of the total energy operator for the particle in the box.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Function
In quantum mechanics, the wave function is a fundamental concept that describes the mathematical embodiment of a quantum system. It typically provides the probability amplitude of a particle's position in space. When you have a particle, like an electron, the wave function tells us where the particle is likely to be found. This probabilistic nature is a key departure from classical physics, where objects have defined paths. Formally, the wave function is usually denoted by the Greek letter psi (\(\psi(x)\)) and is a complex-valued function. The modulus squared of the wave function, \(|\psi(x)|^2\), gives the probability density. This means it predicts how likely it is to find a particle in a small region around a point. A wave function must satisfy certain conditions, like normalization, ensuring the total probability across all space is one. Learning how to manipulate and analyze wave functions is crucial because they allow us to calculate the likelihood of different quantum states, such as energy levels, of a system.
Particle in a Box
The concept of a 'particle in a box' is a simplified model used in quantum mechanics to demonstrate the behavior of a confined particle. Imagine a tiny particle trapped in an infinitely deep box. The walls of the box are impenetrable, and the particle has zero potential energy when inside. In this scenario, the particle's wave function must be zero at the boundaries (because the particle cannot exist beyond the walls). This boundary condition makes the system discrete, meaning the particle can only have certain specific energy levels, termed quantized energy levels. Such quantization is absent in classical physics, where energy can vary continuously. This model is key to understanding how energy quantization arises from physical constraints, providing a foundation for more complex quantum systems. The particle in a box exemplifies how boundary conditions lead to the emergence of discrete energy states.
Eigenfunctions
Eigenfunctions are special wave functions that, when acted upon by a quantum operator, yield a result that is simply a constant (the eigenvalue) times the original function. These are extremely important in quantum mechanics as they represent stable states of a system. The primary condition is given by an eigenvalue equation \(H \psi(x) = E \psi(x)\), where \(H\) is the Hamiltonian (the total energy operator), \(\psi(x)\) is the wave function, and \(E\) is the eigenvalue representing a measurable quantity like energy. For a particle in a box, eigenfunctions take the form of sinusoidal functions, specific solutions satisfying the boundary conditions. When multiple functions are expressed as a single wave function, as in the superposition, they typically do not maintain the form \(E \psi(x)\), hence they usually are not eigenfunctions. This was exactly the situation in the given exercise, where the superposition resulted in a function that was not a true eigenfunction of the energy operator. Understanding eigenfunctions allows us to predict how quantum states evolve over time, as they indicate the probabilistic nature of fundamental forces and particles.

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Most popular questions from this chapter

Suppose that the wave function for a system can be written as \\[ \psi(x)=\frac{\sqrt{3}}{4} \phi_{1}(x)+\frac{\sqrt{3}}{2 \sqrt{2}} \phi_{2}(x)+\frac{2+\sqrt{3} i}{4} \phi_{3}(x) \\] and that \(\phi_{1}(x), \phi_{2}(x),\) and \(\phi_{3}(x)\) are normalized eigenfunctions of the operator \(\hat{E}_{\text {kinetic}}\) with eigenvalues \(E_{1}, 2 E_{1},\) and \(4 E_{1},\) respectively. a. Verify that \(\psi(x)\) is normalized. b. What are the possible values that you could obtain in measuring the kinetic energy on identically prepared systems? c. What is the probability of measuring each of these eigenvalues? d. What is the average value of \(E_{k \text {inetic}}\) that you would obtain from a large number of measurements?

Show that the energy eigenvalues for the free particle, \(E=\hbar^{2} k^{2} / 2 m,\) are consistent with the classical result \(E=(1 / 2) m \mathrm{v}^{2}\)

Are the eigenfunctions of \(\hat{H}\) for the particle in the one-dimensional box also eigenfunctions of the position operator \(\hat{x} ?\) Calculate the average value of \(x\) for the case where \(n=3 .\) Explain your result by comparing it with what you would expect for a classical particle. Repeat your calculation for \(n=5\) and, from these two results, suggest an expression valid for all values of \(n\). How does your result compare with the prediction based on classical physics?

Consider a particle in a one-dimensional box defined by \(V(x)=0, a>x>0\) and \(V(x)=\infty, x \geq a, x \leq 0\) Explain why each of the following unnormalized functions is or is not an acceptable wave function based on criteria such as being consistent with the boundary conditions, and with the association of \(\psi^{*}(x) \psi(x) d x\) with probability. a. \(A \cos \frac{n \pi x}{a}+B \sin \frac{n \pi x}{a}\) b. \(C\left(1-\sin \frac{n \pi x}{a}\right)\) c. \(C x^{3}(x-a)\) d. \(D(a-x) x\) e. \(\frac{E}{\cos (n \pi x / a)}\)

Calculate the expectation values \(\langle x\rangle\) and \(\left\langle x^{2}\right\rangle\) for a particle in the state \(n=5\) moving in a one- dimensional box of length \(2.50 \times 10^{-10} .\) Is \(\left\langle x^{2}\right\rangle=\langle x\rangle^{2} ?\) Explain your answer.

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