Chapter 13: Problem 44
How would you prepare the following compounds from 2 -phenylethanol? More than one step may be required. (a) Styrene \(\left(\mathrm{PhCH}=\mathrm{CH}_{2}\right)\) (b) Phenylacetaldehyde (PhCH \(_{2}\) CHO) (c) Phenylacetic acid \(\left(\mathrm{PhCH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\) (d) Benzoic acid (e) Ethylbenzene (f) 1-Phenylethanol
Short Answer
Step by step solution
Conversion to Styrene
Conversion to Phenylacetaldehyde
Conversion to Phenylacetic Acid
Conversion to Benzoic Acid
Conversion to Ethylbenzene
Conversion to 1-Phenylethanol
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dehydration Reaction
The reaction is categorized as an E1 elimination reaction, which involves several steps:
- First, the hydroxyl (-OH) group in 2-phenylethanol is protonated by the acid, making it a better leaving group.
- Next, a carbocation is formed as the water molecule departs.
- Finally, a proton is removed from the adjacent carbon, leading to the formation of a double bond to yield styrene.
Oxidation Reactions
For converting 2-phenylethanol to phenylacetaldehyde, oxidation is achieved by using pyridinium chlorochromate (PCC). This reagent is gentle enough to stop the oxidation at the aldehyde stage, preventing further transformation to a carboxylic acid. Steps in Oxidation:
- The alcohol group of 2-phenylethanol donates electrons, which PCC accepts, converting the alcohol to an aldehyde.
- This selective oxidation leaves the aldehyde group intact, an essential step for further transformations.
Grignard Reaction
Grignard reagents are organomagnesium compounds such as methylmagnesium bromide (CH₃MgBr), which form when halides react with magnesium in a dry ether environment.
Here’s how the Grignard reaction proceeds:
- First, acetophenone, a compound with a carbonyl group (C=O), is treated with the Grignard reagent.
- The Grignard reagent acts as a nucleophile, attacking the electrophilic carbon of the carbonyl group.
- A new carbon-carbon bond forms, creating an alkoxide intermediate.
- Upon hydrolysis, the alkoxide converts into an alcohol, specifically 1-phenylethanol in this case.
Hydrogenation
Using hydrogen gas in the presence of a metal catalyst, like palladium or platinum, hydrogenation proceeds smoothly:
- The catalyst provides a surface for the alkene bonds in styrene to interact with hydrogen gas.
- These double bonds (C=C) open up, allowing hydrogen atoms to add to the carbon atoms, reducing the alkene to an alkane.
- This results in the conversion of styrene to ethylbenzene, achieving the desired reduction.
Friedel-Crafts Reaction
For the formation of acetophenone—a precursor in the synthesis of 1-phenylethanol—the Friedel-Crafts acylation reaction comes into play:
- An acyl chloride, such as ethanoyl chloride, reacts with benzene in the presence of a Lewis acid catalyst, like aluminum chloride (AlCl₃).
- The Lewis acid facilitates the formation of an acylium ion from the acyl chloride, which then attacks the electron-rich aromatic ring.
- The electrophilic aromatic substitution results in the formation of acetophenone.