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How many absorptions would you expect (S)-malate, an intermediate in carbohydrate metabolism, to have in its \({ }^{1} \mathrm{H}\) NMR spectrum? Explain.

Short Answer

Expert verified
(S)-malate has four distinct proton signals in its NMR spectrum.

Step by step solution

01

Determine the Structure of (S)-malate

(S)-malate is the (S)-enantiomer of malic acid. Its structure includes a hydroxyl group (-OH), two carboxylic acid groups (-COOH), and one methine group (-CH-) bonded to a chiral center. When drawing the structure, note the key protons attached to this framework.
02

Identify Unique Proton Environments

In NMR spectroscopy, each unique proton environment gives rise to a separate signal. Examine the structure to identify different sets of equivalent protons. For (S)-malate, there are distinct environments: the proton on the methine group (-CH-), the protons on the hydroxyl group (-OH), and distinct protons from the two carboxyl groups, as well as the -CH_2- group.
03

Count Equivalent Sets of Protons

List each set of equivalent protons. (S)-malate has one set of protons from the -CH- group, one set from the -OH group, two sets of protons from the -COOH groups (if we assume they're equivalent under experimental conditions), and a set from the -CH_2- group, making a total of four unique environments.
04

Predict the Number of Expected Signals

Based on the analysis, you would expect four signals in the NMR spectrum for (S)-malate: one for each unique group of protons identified in Step 3. The signal from the -OH group might be broad and somewhat distinct depending on the condition of the spectrum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Environments
To understand NMR spectroscopy and how many signals you might expect for a compound like (S)-malate, it's crucial to delve into the concept of proton environments. In \(^1H\) NMR spectroscopy, each chemically distinct hydrogen atom, or proton, resides in a unique environment. This uniqueness often stems from differences in electronic environments or the stereochemistry surrounding the protons.
  • Different proton environments correspond to protons that are in various chemical bonds or positions within the molecule.
  • Protons that experience the same electronic shield or have identical surroundings typically constitute equivalent environments, leading to the same NMR signals.
  • For (S)-malate, distinctive environments arise from groups like -CH-, -OH, -COOH, and -CH_2-, each varying due to their chemical and spatial positioning.
Understanding these environments is key to predicting the number of spectral signals.
Chiral Centers
The presence of chiral centers significantly influences the NMR spectra of compounds. A chiral center is typically a carbon atom bonded to four different groups, leading to stereochemistry that affects the chemical environments of nearby protons.
  • (S)-malate, for instance, has a chiral center which is pivotal in determining its NMR profile.
  • Chirality introduces unique spatial configurations, which means that protons near the chiral center can exist in non-equivalent environments.
  • Therefore, the protons attached to such centers can give rise to distinct signals compared to protons in symmetric environments.
This aspect of chiral centers allows for detailed analytical insights, enhancing our understanding of complex molecular stereochemistry.
Signal Prediction
Predicting signals in NMR spectroscopy involves recognizing and appraising the equivalent proton sets within a molecule. Signal prediction entails counting how many separate groups of protons, each with unique environments, exist.
  • For (S)-malate, this means identifying the methine proton (-CH-), the hydroxyl proton (-OH), the two carboxylic acid protons (-COOH), and the methylene protons (-CH_2-).
  • If protons are equivalent, they produce one signal. Distinct sets naturally lead to separate signals on the spectrum.
  • The expected number of signals correlates directly with the number of unique proton environments, producing a clear NMR pattern.
Signal prediction is pivotal in interpreting NMR spectra and understanding molecular structures.
(S)-malate
(S)-malate itself is an interesting compound to study with NMR spectroscopy as it is an intermediate in carbohydrate metabolism. Its structure -- featuring elements such as the hydroxyl, carboxyl, and methine groups -- provides a rich environment for studying NMR signals.
  • When examining (S)-malate under NMR, we anticipate four main signals, corresponding to its unique proton environments.
  • The unique arrangement due to the chiral center aids in the differentiation of signals originating from the structurally varied protons.
  • This prediction aligns with the four distinct proton environments, making (S)-malate a fantastic candidate for illustrating fundamental principles of NMR.
By seeking the nuances within (S)-malate’s structure, one can gain deeper insights into the broader concepts of proton environments and their significance in chemical analysis.

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Most popular questions from this chapter

Propose structures for compounds that fit the following descriptions: (a) A hydrocarbon with seven lines in its 13 C NMR spectrum (b) A six-carbon compound with only five lines in its 13 C NMR spectrum (c) A four-carbon compound with three lines in its \({ }^{13}\) C NMR spectrum

How many kinds of electronically nonequivalent protons are present in each of the following compounds, and thus how many NMR absorptions might you expect in each? (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}\) (b) \(\mathrm{CH}_{3} \mathrm{OCH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NO}_{2}\) (d) Toluene (e) 2 -Methylbut-1-ene (f) cis-Hex-3-ene

A 13 C NMR spectrum of commercially available pentane-2,4-diol shows five peaks at \(23.3,23.9,46.5,64.8,\) and \(68.1 \delta .\) Explain.

Carboxylic acids \(\left(\mathrm{RCO}_{2} \mathrm{H}\right)\) react with alcohols \(\left(\mathrm{R}^{\prime} \mathrm{OH}\right)\) in the presence of an acid catalyst. The reaction product of propanoic acid with methanol has the following spectroscopic properties. Propose a structure. $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COH} \quad \frac{\mathrm{O}}{\mathrm{H}^{+} \text {catalyst }} \quad ? $$ Propanoic acid \(\mathrm{MS}: \mathrm{M}^{+}=88\) \(\mathrm{IR}: 1735 \mathrm{~cm}^{-1}\) 1H NMR: \(1.11 \delta(3 \mathrm{H},\) triplet, \(J=7 \mathrm{~Hz}) ; 2.32 \delta(2 \mathrm{H},\) quartet, \(J=7 \mathrm{~Hz})\) \(3.65 \delta(3 \mathrm{H},\) singlet \()\) \({ }^{13} \mathrm{C} \mathrm{NMR}: 9.3,27.6,51.4,174.6 \delta\)

Propose a structure for compound \(\mathbf{C},\) which has \(\mathrm{M}^{+}=86\) in its mass spectrum, an IR absorption at \(3400 \mathrm{~cm}^{-1}\), and the following \({ }^{13} \mathrm{C}\) NMR spectral data: Compound C Broadband-decoupled \({ }^{13} \mathrm{C}\) NMR: \(30.2,31.9,61.8,114.7,138.4 \delta\) DEPT-90: 138.4 \& DEPT-135: positive peak at \(138.4 \delta\); negative peaks at 30.2,31.9,61.8 , \(114.7 \delta\)

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