Chapter 1: Problem 30
Convert the following molecular formulas into line-bond structures that are consistent with valence rules: (a) \(\mathrm{C}_{3} \mathrm{H}_{8}\) (b) \(\mathrm{CH}_{5} \mathrm{~N}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) (2 possibilities) (d) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{Br}\) (2 possibilities) (e) \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}\) (3 possibilities) (f) \(\mathrm{C}_{3} \mathrm{H}_{9} \mathrm{~N}\) (4 possibilities)
Short Answer
Step by step solution
Understand Valence Rules
Convert C3H8 to Line-Bond Structure
Convert CH5N to Line-Bond Structures
Convert C2H6O to Line-Bond Structures
Convert C3H7Br to Line-Bond Structures
Convert C2H4O to Line-Bond Structures
Convert C3H9N to Line-Bond Structures
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Formulas
- \(C_3H_8\) represents propane, indicating it consists of three carbon atoms and eight hydrogen atoms.
- \(CH_5N\) suggests a compound comprising one carbon, five hydrogens, and one nitrogen, such as methyl amine.
Line-bond Structures
- Lines portray bonds between atoms — single, double, or triple, indicating the type of bond.
- If the carbon is involved, assume that each line extended from it is a C-H bond unless stated otherwise.
- In propane \(C_3H_8\), the structure \(- H_3C - CH_2 - CH_3 -\) illustrates each carbon atom forming single bonds with enough hydrogen atoms to satisfy its four-bond requirement.
Isomers
- \(C_2H_6O\) can represent both ethanol and dimethyl ether, each having distinct structures and uses.
- Similarly, \(C_3H_7Br\) can be either 1-bromopropane or 2-bromopropane.
Organic Chemistry
- These include alcohols like ethanol in \(C_2H_6O\), where the -OH group is added to the hydrocarbon framework.
- Amines, another class of organic compounds, include things like methyl amine (\(CH_5N\)).
Bonding in Molecules
- Single bonds, like in propane (\(C_3H_8\)), provide flexibility within the molecule.
- Double bonds, present in structures such as vinyl alcohol (an isomer of \(C_2H_4O\)), create rigidity and influence reactivity.
- Triple bonds, though not shown in the current examples, arise in other types of organic molecules, like alkynes, introducing even more complexity.