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Propose structures for compounds that fit the following data: (a) \(\mathrm{A}\) ketone with \(\mathrm{M}^{+}=86\) and fragments at \(\mathrm{m} / \mathrm{z}=71\) and \(\mathrm{m} / \mathrm{z}=43\) (b) An alcohol with \(\mathrm{M}^{+}=88\) and fragments at \(\mathrm{m} / \mathrm{z}=73, \mathrm{~m} / \mathrm{z}=70\), and \(m / z=59\)

Short Answer

Expert verified
Compound (a) is 2-pentanone; compound (b) is 2-butanol.

Step by step solution

01

Start with the Mass-to-Charge Ratio

Identify the molecular structures based on the given mass-to-charge (m/z) ratios for the given compounds. For compound (a), the molecular ion peak \(\mathrm{M}^+ = 86\) suggests a molecular weight of 86. For compound (b), the molecular ion peak \(\mathrm{M}^+ = 88\) suggests a molecular weight of 88.
02

Propose Structure for Compound (a)

For a ketone with molecular weight 86, consider common functionalized carbon chains. One possibility is 2-pentanone, where the molecular formula is \(\mathrm{C}_5\mathrm{H}_{10}\mathrm{O}\). This fits the molecular weight and can fragment to yield \(m/z = 43\) for a common acyl fragment \(\mathrm{C}_2\mathrm{H}_3\mathrm{O}^+\), as well as \(m/z = 71\), which can be a result of losing an ethyl group (mass 15 from \(\mathrm{C}_3\mathrm{H}_7\mathrm{O}^+\)).
03

Propose Structure for Compound (b)

For an alcohol with molecular weight 88, consider simple alcohol structures that fit the mass. One possibility is 2-butanol, having the molecular formula \(\mathrm{C}_4\mathrm{H}_{10}\mathrm{O}\). It can produce a fragment at \(m/z = 73\) by losing a methyl group (mass 15 from \(\mathrm{C}_3\mathrm{H}_7\mathrm{O}^+\)), at \(m/z = 70\) if two hydrogens are lost along with the methyl group, and \(m/z = 59\) through fragmentation of the carbon chain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ketone Structure Determination
Determining the structure of a ketone using mass spectrometry involves analyzing the mass-to-charge (m/z) ratio of its fragmented ions. Ketones are characterized by a carbonyl group (C=O) nestled between carbon atoms. In mass spectrometry, ketones often fragment to produce various ions that fall apart in predictable patterns.

For a ketone with a molecular ion peak at M+ = 86, such as the example given in the problem, one potential structure is 2-pentanone. This corresponds to the molecular formula C5H10O, matching the weight of 86. Key fragments that help in confirming this structure include:
  • An m/z = 43 fragment, often seen with ketones, representing a common acyl cation ( C2H3O+).
  • An m/z = 71 fragment, potentially formed by losing an ethyl group (C2H5), resulting in C3H7O+.
Identifying these specific fragments in the mass spectrum helps to confidently determine the ketone's structure. The ability to break down a molecule and interpret the resulting mass fragments is crucial in defining the carbon backbone and locating the functional groups.
Alcohol Structure Determination
In mass spectrometry, alcohols can be identified and differentiated by the analysis of the mass-to-charge ratio of their fragmented ions. Alcohols contain the hydroxyl group (-OH), which influences their fragmentation pattern in a mass spectrometer due to the rupture of bonds adjacent to this group.

For an alcohol with a molecular ion peak at M+ = 88, such as 2-butanol, the analysis begins by looking for major fragment ions consistent with typical alcohol fragmentation patterns. Consider C4H10O, weighing in at 88, as a potential candidate. Some characteristic fragments include:
  • An m/z = 73 fragment produced by the loss of a methyl group (C3H7O+), a common occurrence in alcohols.
  • An m/z = 70 fragment resulting from the loss of two hydrogens, in addition to the methyl group, affecting the hydroxyl-bearing carbon.
  • An m/z = 59 fragment due to breaking the carbon chain, which is a typical fragmentation pattern for alcohols.
By examining these characteristic fragment peaks, the structure of the alcohol can be effectively proposed, showing how the hydroxyl group influences the breakdown pattern.
Mass-to-Charge Ratio Analysis
The mass-to-charge ratio (m/z) is a fundamental concept in mass spectrometry used to identify molecular structures by analyzing their charged fragments. It combines the mass of an ion with its charge, providing critical insight into the structure of an unknown compound. Understanding m/z is crucial for interpreting mass spectra and identifying the molecular ion, which indicates the entire unfragmented molecule in the spectrum.

Given the exercise's ketone and alcohol, interpreting their m/z values involves:
  • Molecular Ion Peak: For both compounds, the M+ peak represents their complete molecular weight, which helps in determining possible molecular formulas.
  • Fragment Ions: Analyzing smaller m/z peaks, produced by the cleavage of chemical bonds, aids in piecing together potential structures by matching them with known fragmentation patterns.
  • Charge of Ions: Mass spectrometers typically produce singly charged ions, making the m/z value essentially equivalent to the ion's mass.
By mapping ion peaks in the spectra to known fragmentation patterns, chemists can deduce structural features and arrive at probable structures for the molecules under investigation. Understanding m/z analysis allows for logically piecing together fragmented information to rebuild the complete molecular story.

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Most popular questions from this chapter

The nitrogen rule of mass spectrometry says that a compound containing an odd number of nitrogens has an odd-numbered molecular ion. Conversely, a compound containing an even number of nitrogens has an even-numbered \(\mathrm{M}^{+}\) peak. Explain.

Ketones undergo a reduction when treated with sodium borohydride, \(\mathrm{NaBH}_{4}\). What is the structure of the compound produced by reaction of butan-2-one with \(\mathrm{NaBH}_{4}\) if it has an IR absorption at \(3400 \mathrm{~cm}^{-1}\) and \(\mathrm{M}^{+}=74\) in the mass spectrum?

A knowledge of molar absorptivities is particularly useful in biochemistry, where UV spectroscopy can provide an extremely sensitive method of detection. Imagine, for instance, that you wanted to determine the concentration of vitamin \(A\) in a sample. If pure vitamin \(A\) has \(\lambda_{\max }=325(\epsilon=50,100)\), what is the vitamin A concentration in a sample whose absorbance at \(325 \mathrm{~nm}\) is \(A=0.735\) in a cell with a pathlength of \(1.00 \mathrm{~cm} ?\)

Which is stronger, the \(\mathrm{C}=\mathrm{O}\) bond in an ester \(\left(1735 \mathrm{~cm}^{-1}\right)\) or the \(\mathrm{C}=\mathrm{O}\) bond in a saturated ketone \(\left(1715 \mathrm{~cm}^{-1}\right) ?\) Explain.

Halogenated compounds are particularly easy to identify by their mass spectra because both chlorine and bromine occur naturally as mixtures of two abundant isotopes. Chlorine occurs as \({ }^{35} \mathrm{Cl}(75.8 \%)\) and \({ }^{37} \mathrm{Cl}(24.2 \%)\); bromine occurs as \({ }^{79} \mathrm{Br}(50.7 \%)\) and \({ }^{81} \mathrm{Br}(49.3 \%)\). At what masses do the molecular ions occur for the following formulas? What are the relative percentages of each molecular ion? (a) Bromomethane, \(\mathrm{CH}_{3} \mathrm{Br}\) (b) 1-Chlorohexane, \(\mathrm{C}_{6} \mathrm{H}_{13} \mathrm{Cl}\)

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