Question

How might you prepare each of the following molecules using a nucleophilic substitution reaction at some step?

$d.C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}N{H}_2$

Short answer

$C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br+\left(excess\right)N{H}_3\to C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}N{H}_2+NaBr$

Step-by-step solution

SN2 reaction

It is a nucleophilic substitution reaction in which old bond is break and new bond is formed both the process occur simultaneously. Hence, it’s a single step reaction.

The two reacting species are involved in the rate determining steps.

Formation of CH3CH2CH2CH2NH2

Here, the nucleophilic substitution occur where NaBr is produced and desired product is formed.

The two reacting species are involved in the rate determining steps.

$C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br+excessN{H}_3\to C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}N{H}_2+NaBr$

Substitution reaction