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Question: Which of the following alcohols could notbe made selectively by hydroboration–oxidation of an alkene? Explain.

Short Answer

Expert verified

Answer

Not possible

Step by step solution

01

Step 1: Anti-markovnikov’s rule

In hydroboration-oxidation reaction two steps occur:

  • Hydroboration- It occurs in an anti-Markovnikov manner, where hydrogen (from BH3) attaches to the more substituted carbon and BH2to less substituted carbon in double-bonded carbon. It is syn addition which means that the hydroboration takes place on the same face of the double bond.
  • Oxidation step involves the replacement of BH2with hydroxyl group.
02

 Step 2: Alcohol possible or not

Given alcohol is possible when a double bond is between C2and C3 as both are equally substituted but not in the case of a double bond between C1and C2 as hydrogen attaches to the more substituted carbon. As both the carbon are equally substituted so other alcohol, isopentanol is also possible. This alcohol is not made selectively.

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Most popular questions from this chapter

Compound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a palladium catalyst. On treatment of A with dilute sulfuric acid, dehydration occurred and an optically inactive alkene B,C11H14, was the major product. Alkene B, on ozonolysis, gave two products. One product was identified as propanal,CH3CH2CHO. Compound C, the other product, was shown to be a ketone,C8H8O. How many degrees of unsaturation does A have? Write the reactions, and identify A, B, and C.

Compound A has the formula C10H16. On catalytic hydrogenation over palladium, it reacts with only 1 molar equivalent of H2. Compound A also reacts with ozone, followed by zinc treatment, to yield a symmetrical diketone, B(C10H16O2).

Write the reactions.

Show the structures of alkenes that give the following products on oxidative cleavage with in acidic solution.

Compound A has the formula C8H8. It reacts rapidly with KMnO4to giveCO2 and a carboxylic acid, B (C7H6O2), but reacts with only 1 molar equivalent of H2on catalytic hydrogenation over a palladium catalyst. On hydrogenation under conditions that reduce aromatic rings, 4 equivalents ofH2 are taken up and hydrocarbon C (C8H16)is produced. What are the structures of A, B, and C? Write the reactions.

Evidence that cleavage of 1,2-diols by HIO4occurs through a five membered cyclic periodate intermediate is based on kinetic data—the measurement of reaction rates. When diols A and B were prepared and the rates of their reaction withHIO4were measured, it was found that diol A cleaved approximately 1 million times faster than diol B. Make molecular models of A and B and of potential cyclic periodate intermediates, and then explain the kinetic results

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