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Question:Predict the products of the following reactions. Don’t worry about thesize of the molecule; concentrate on the functional groups.

Short Answer

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Answer

Products of the reactions are:

Step by step solution

01

Product of reaction (a)

In the first reaction reagent is bromine, and the reactant is cholesterol. In cholesterol, an alkene is a nucleophile, and it is reactive; therefore, double bonds of an alkene will react with the bromine and will for vicinal- dibromide or 1,2- dibromide.

02

Product of reaction (b)

In this reaction, the reactant is an unsymmetrical alkene. When treated with the reagent HBr, it will follow Markovnikov’s rule, and a hydrogen atom and bromine will attach on both sides of the double bond. According to Markovnikov’s rule, a hydrogen atom will attach to the carbon atom having more hydrogens, and bromine will attach to that carbon atom which is having less number of hydrogen atoms.

Hence, the product of the reaction is:

03

Product of reaction (c)

In this reaction, the reagent is osmium Tetraoxide, also known as osmic acid. When cholesterol is treated with this reagent, double bonds of reactant will react with the reagent and produce 1,2-diol.

04

Product of reaction (d)

When the reactant cholesterol is treated with the reagent, the double bond of the reactant will react with the reagent. This reaction is a hydroboration- oxidation reaction, and a hydrogen atom and hydroxide will add to both sides of the double bond according to anti- Markovnikov’s rule.

05

Product of reaction (e)

When our reactant, i.e., cholesterol, is reacted with the reagent, the alkene bond will be converted into a cyclopropane ring, and this reaction is known as Simmons- Smith reaction.

Hence, the product of the reaction is:

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Most popular questions from this chapter

An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent ofH2 over a palladium catalyst. Hydrocarbon A also reacts withOsO4 to give diol B. When oxidized withKMnO4 in acidic solution, A gives two fragments. One fragment is propanoic acid, CH3CH2CO2H, and the other fragment is ketone C. What are the structures of A, B, and C? Write all reactions, and show your reasoning.

Compound A has the formula C10H16. On catalytic hydrogenation over palladium, it reacts with only 1 molar equivalent of H2. Compound A also reacts with ozone, followed by zinc treatment, to yield a symmetrical diketone, B(C10H16O2).

Write the reactions.

Compound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a palladium catalyst. On treatment of A with dilute sulfuric acid, dehydration occurred and an optically inactive alkene B,C11H14, was the major product. Alkene B, on ozonolysis, gave two products. One product was identified as propanal,CH3CH2CHO. Compound C, the other product, was shown to be a ketone,C8H8O. How many degrees of unsaturation does A have? Write the reactions, and identify A, B, and C.

Question: What product would you expect to obtain from addition of to 1,2-dimethyl-cyclohexene? Show the stereochemistry of the product.

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(a) How many degrees of unsaturation doesα-terpinene have?

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