Question

How would you prepare the following compound using a Michael reaction?

Short answer

By the reaction between pent-1-ene-3-one and nitroethane we can prepare the given compound.

Step-by-step solution

Michael addition and donor group

First, we have to find out the Michael addition and donor group in the given compound since the carbonyl group is the accepter and then give number 1,2,3 to the carbon atoms of the compound after identification of the Michael addition and donor group break the bond between them and we get the reactant of this reaction.

The chemical reaction occurs: