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Give IUPAC names for the following substances (red 5 O, blue 5 N):

Short Answer

Expert verified
  1. m-isopropyl phenol
  2. o-nitrobenzoic acid

Step by step solution

01

IUPAC nomenclature

It is a method to give a scientific name to the organic compounds recommended by the Indian Union of Pure and Applied Chemistry.

02

Nomenclature of benzene

IUPAC rules used for naming of benzene

  1. Name the parent aromatic benzene ring
  2. Assign numbering to the substituents
  3. Assign the first number to the bulky group
  4. Halogens get the priority
  5. Write the name of the molecule in alphabetic
03

To identify the IUPAC from the structure of compound A

  1. The parent ring is a benzene ring attached with OH so phenol
  2. Isopropyl is present at the meta position to the OH group
  3. So, IUPAC's name is m-isopropyl phenol
  4. So, the structure must be:

04

To identify the IUPAC from the structure of compound B

  1. The parent ring is a benzene ring attached with COOH which is acid so benzoic acid
  2. The Nitro group is present at the ortho position to the COOH group
  3. So, IUPAC name is o-nitro benzoic acid
  4. So, the structure must be:

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Most popular questions from this chapter

To be aromatic, a molecule must have 4n+2 p electrons and must have a planar, monocyclic system of conjugation. Cyclodecapentaene fulfills one of these criteria but not the other and has resisted all attempts at synthesis. Explain.

Propose structures for compounds that fit the following descriptions:

(a) C10H141HNMR: 7.18โ€‰ฮด(4 H, broad singlet);2.70โ€‰ฮด(4 H, quartet, J = 7 Hz); 1.20โ€‰ฮด(6 H, triplet, J =7 Hz) IR:745โ€‰cm-1.

(b)C10H141HNMR:7.0โ€‰ฮด(4 H, broad singlet);2.85โ€‰โ€‰ฮด(1 H, septet, J = 8 Hz);2.28โ€‰โ€‰ฮด(3 H, singlet);1.20โ€‰โ€‰ฮด(6 H, doublet, J = 8 Hz) IR:825โ€‰cm-1.

Propose structures for aromatic hydrocarbons that meet the following descriptions:

(a) C9H12; gives only one C9H11Brproduct on substitution of hydrogen on the aromatic ring with bromine

(b)C10 H14; gives only one C10H13Clproduct on substitution of hydrogen on the aromatic ring with chlorine

(c) C8H10; gives three C8H9Brproducts on substitution of hydrogen on the aromatic ring with bromine

(d)C10 H14 ; gives two C10H13Clproducts on substitution of hydrogen on the aromatic ring with chlorine

N-Phenylsydnone, so-named because it was first studied at the University of Sydney, Australia, behaves like a typical aromatic molecule. Explain, using the Hรผckelโ€™s 4n+2rule .

N-phenylsydnone

Azo dyes are the major source of artificial color in textiles and food. Part of the reason for their intense coloring is the conjugation from an electron-donating group through the diazo bridge (-N=N-)to an electron-withdrawing group on the other side. For the azo dyes below, draw a resonance form that shows how the electron-donating group is related to the electron-withdrawing group on the other side of the diazo bridge. Used curved arrows to show how the electrons are reorganized.

a.

Methyl orange

b.

C.I. Acid Red 74

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