Question

What products would you expect from the following reactions?

c. ${\mathbf{CH}}_{\mathbf{3}}{\mathbf{CH}}_{\mathbf{2}}{\mathbf{CH}}_{\mathbf{2}}{\mathbf{CH}}_{\mathbf{2}}\mathbf{C}\mathbf{\equiv }{\mathbf{CCH}}_{\mathbf{3}}\mathbf{+}\mathbf{HBr}$

Short answer

In this the alkyne is converted to an alkene by the halogenation that the three out of one triple bond is broken foe the addition of halide but the halogen and hydrogen are added always in trans geometry.

Step-by-step solution

Markovnikov reactions

In this the alkyne is converted to an alkene by the halogenation that the three out of one triple bond is broken foe the addition of halide but the halogen and hydrogen are added always in trans geometry.

Reaction of alkyne with an alkyl halide CH3CH2CH2CH2C≡CCH3+1HBr

When alkyne reacts with alkyl halide they undergo additional reactions to form a halogen-substituted alkene. Alkyne follows Markovnikov regiochemistry in which one halogen atom and one hydrogen atom are always added in a trans relationship with each other.

Two products are obtained from the addition of an internal alkyne