Question

The following alkyl bromide can be made by HBr addition to three different alkenes. Show their structures.

Short answer

Alkyl halides are also termed haloalkanes. The hydrogen atoms are substituted with halogen atoms like fluorine, chlorine, or bromine to obtain haloalkanes.

Haloalkanes can be classified into mono, di, or trihaloalkane based on the number of halogen atoms present in them.

Step-by-step solution

Step-by-Step solutionStep 1: Alkyl halides

Alkyl halides are also termed haloalkanes. The hydrogen atoms are substituted with halogen atoms like fluorine, chlorine, or bromine to obtain haloalkanes.

Haloalkanes can be classified into mono, di, or trihaloalkane based on the number of halogen atoms present in them.

Structure of the alkyl bromide formed by the HBr addition to three alkenes

The structure of the given alkyl bromide is 1-bromo-1-ethyl-3-methylcyclohexane.

In the second step of the addition reaction, the bromine strikes the carbon with a positive charge in the carbocation. Hence, the alkenes must have a double bond in a way that abstracting hydrogen from the hydrogen halide leads the carbon connected to bromine to get attached to get a positive charge.

Structure of the alkyl bromide formed by the HBr addition to three alkenes