Chapter 19: Q83E (page 648)
Propose structures for ketones or aldehydes that have the following 1H NMR spectra:
(a) C9H10O2
IR: 1695 cm-1
(b) C4H6O
IR: 1690 cm-1
Short Answer
The structure of the compound is:
Step by step solution
Identify compound a from IR
As the IR peak is observed at 1730 cm-so the compound must contain the aldehyde functional group or a derivate of an aldehyde group.
Identify compound a from NMR
As per the NMR graph, the peak at the 6.98 and 7.81 are due to the aromatic ring which is a compound containing the aromatic ring and the peak at 4.08 shows quartet that is methylene group is present with a methyl group and the 1.44 is showing a triplet by the methyl hydrogen due to the 2H of the methylene group so the structure must be:
Identify compound b from IR
As the IR peak is observed at 1690 cm-so the compound must be contain the ketone functional group or a derivate of an carbonyl group.
Identify compound b from NMR
The peak observed at 9.57 is due to the proton of the carbonyl and the molecular formula is given we can find the unsaturation and the unsaturation is 1 as:
That is one double bond is present in the molecule.
The longest peak at 1.86 is due to the methylene and the peak at 6.0 and 6.31 are due to the proton of the alkene so, the compound must be:
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