Question

What are products of the following reactions?

Short answer

a)

b)

c)

d)

e)

f)

Step-by-step solution

Some conclusions

1. H₂ in presence of Pd/C becomes strong reducing agent and form primary alkane from alkyne.

2. H₂ in presence of lindlar catalyst stops the reaction at alkene stage.

3. Na/NH₃cannot be used to reduce terminal alkynes, because Na will remove the hydrogen that is attached to the sp carbon of the terminal alkyne.

4. Hydroboration-oxidation= In this anti markoniv addition takes place.

Final answer

a) H₂ in presence of Pd/C becomes strong reducing agent and form primary alkane from alkyne.

b) H₂ in presence of lindlar catalyst stops the reaction at alkene stage.

c) Na/NH₃cannot be used to reduce terminal alkynes, because Na will remove the hydrogen that is attached to the sp carbon of the terminal alkyne.

d)Hydroboration-oxidation= In this anti markoniv addition takes place.

e)Hydroboration-oxidation= In this anti markoniv addition takes place. But here both triple bonded carbon atoms have same number of hydrogen atoms so here two products will form.

f) In presence of H₂O and H₂SO₄ ketone formation is there. But here both triple bonded carbon atoms have same number of hydrogen atoms so here two products will form.