Chapter 18: Q85P (page 919)
Identify A–J:
Short Answer
Product A: Acetophenone
Product B: 1- (3-nitrophenyl) ethanone
Product C:ethylbenzene
Product D:benzoic acid
Product E: (1-bromoethyl) benzene
Product F: (1-methoxyethyl) benzene and styrene
Product G: (1-iodoethyl) benzene
Product H: Styrene
Product I: (2-bromoethyl) benzene
Product J: 3-phenylpropanenitrile
Step by step solution
Electrophilic aromatic substitution
A benzene has an electron rich nucleus and undergoes various electrophilic aromatic substitution reactions. The electrophilic substituted products are transformed into other functional groups by functional group interconversion.
Identifying the products A-J
In the given reactions, benzene reacts with the acetyl chloride AlCl3and water to form product A, acetophenone. This reacts with HNO3 and H2SO4to form product B, 1-(3-nitrophenyl) ethanone.
The product A reacts with hydrazine, HO-, and heat to form product C, ethylbenzene. This product reacts with H2CrO4and heat to form product D, benzoic acid. The product C reacts with the bromine and light to form product E, (1-bromoethyl) benzene.
This further reacts with CH3O-to form product F, (1-methoxyethyl) benzene and styrene. This further reacts with HI and heat to form product G, (1-iodoethyl) benzene. The product E also reacts with CH33CO-to form product H, styrene.
This further reacts with HBr and peroxide to form product I, (2-bromoethyl) benzene. This further reacts with cyanide to form product J, 3-phenylpropanenitrile.
Predicting the products of the reaction
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