Question

Draw the structure for each of the following:

a. m-ethylphenol

b. p-nitrobenzenesulfonic acid

c. (E)-2-phenyl-2-pentene

d. o-bromoaniline

e. 4-bromo-1-chloro-2-methylbenzene

f. m-chlorostyrene

g. o-nitro anisole

i. 2,4-dichloromethylbenzene

f. m-chlorobenzoic acid

Short answer

Compound A is m-ethyl phenol

Phenol is the compound in which the hydroxyl group directly attacked the benzene ring and the substituent ethyl group is present at the meta position to the hydroxyl group as shown:

Compound B is p-nitro benzene sulphonic acid

As the same suggests the parent ring is benzene sulphonic acid the sulphonic group is attached to a benzene ring and the nitro group is present at the para as

Compound C is E-2-phenyl,2-pentene

As given the parent chain is pentene in which unsaturated double bond is at C2 carbon and phenyl group is also present at C2 carbon and the pentene is arranged in a transform that the substituted atom in a transform that’s why E is used so structure must be:

Step-by-step solution

Structure of compounds A, B, C

Compound A is m-ethyl phenol

Phenol is the compound in which the hydroxyl group directly attacked the benzene ring and the substituent ethyl group is present at the meta position to the hydroxyl group as shown:

Compound B is p-nitro benzene sulphonic acid

As the same suggests the parent ring is benzene sulphonic acid the sulphonic group is attached to a benzene ring and the nitro group is present at the para as

Compound C is E-2-phenyl,2-pentene

As given the parent chain is pentene in which unsaturated double bond is at C2 carbon and phenyl group is also present at C2 carbon and the pentene is arranged in a transform that the substituted atom in a transform that’s why E is used so structure must be:

 Step2: structure of compounds D, E, F

Compound D is o-Bromo aniline

The structure of compound D has aniline as an apparent ring which means the amine group is attached to benzene and the Bromo is present as a side substituent on the ortho position.

Compound E is 4-Bromo 1-chloro 2-methyl benzene

According to the given name benzene is tri-substituted with Bromo, chloro, and a methyl group at positions 4,1 and 2 so the structure is:

Compound F is m-chloro styrene

Here, the parent ring is styrene a benzene ring is attached to the vinyl unsaturated protons, and the chloro group is present at the meta position as:

m-chloro styrene

Structure of compounds G, H, I

Compound G is o-nitro anisole

As the name suggests the parent’s ring is anisole the benzene ring is connected to the methoxy group and the nitro group is present at the ortho position which is next to the methoxy group.

Compound H is 2,4 dichloro methylbenzene

The structure of the given compound has methyl benzene as the parent ring and the chloro group is present at 2and and 4rth positions as given:

Compound I is m-chloro benzoic acid

As per the given name, the carboxylic acid group is connected to benzene so benzoic acid and chloro are present at the meta position so, the compound is m-chlorobenzene acid and the structure is as followed: