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Match each of the 1HNMR spectra with one of the following compounds:

a.

b.

c.

Short Answer

Expert verified

a.

b.

c.

Step by step solution

01

Step-by-Step SolutionStep 1: Identifying the signals in first spectrum

a. In the given spectrum, two signals are shown.Doublet has lowest frequency and the other signal only has one hydrogen. It indicates that the given compound is 2-bromopropane. The structure is given below.

Structure of (a)

02

Identifying signals in second spectrum

b. The given spectrum shows three signals. Two signals are triplets which have highest and lowest frequency. So the given spectrum suggests that it is compound 1-nitropropane. The structure of the compound is given below.

Structure of (b)

03

Identifying signals in third spectrum

c. There are three signalsshown in the spectrum. They are singlet, triplet, and quartet. This suggests that the compound is ethyl methyl ketone. Its structure is given below.

Structure of (c)

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