Question

Question: What are the products of the following reactions?

a.

b.

c.

d.

e.

f.

g.

h.

i.

Short answer

a.

b.

c.

d.

e.

f.

g.

h.

i.

Step-by-step solution

Reaction of heterocyclic compounds

Aromatic five-membered heterocyclic compounds get subjected to the electrophilic aromatic substitution, preferably at the second position. The intermediate acquired by adding a substituent to this position is more stable than the one at the third position.

Predicting the products of the reaction

a. In this reaction, the pyrrolidine reacts with the benzoyl chloride to form phenyl (pyrrolidin-1-yl) methanone as the product. The reaction is shown below.

Reaction (a)

b. In this reaction, 2-bromopyridine reacts with and heat to form pyridin-2(1H)-one as the product. The reaction is shown below.

Reaction (b)

c. In this reaction, 1-bromobutane reacts with the cyanide followed by H₂ and Raney nickel to form pentanamine. The reaction is shown below.

Reaction (c)

d. In this reaction, 2-methylfuran reacts with the acetyl chloride to form 1-(5-methylfuran-2-yl) ethanone as the product. The reaction is shown below.

e. In this reaction 2-chloropyridine reacts with the phenyllithium to generate 2-phenylpyridine as the product. The reaction is shown below.

f. In this reaction, the cyclcohexananmine reacts with 1-bromopropane to form N-propylcyclohexanamine. The reaction is shown below.

g. In this reaction, the pyrrole reacts with the benzenediazonium to form (E)-2-(phenyldiazenyl)-1H-pyrrole as the product. The reaction is shown below.

Reaction (g)

h. In this reaction, 2-methylpyridine reacts with and 1-bromopropane to form 2-butylpyridine as the product. The reaction is shown below.

i. In this reaction, 2-bromothiophene reacts with the Mg, , carbon dioxide, and HCl to form thiophene-2-carboxylic acid as the product. The reaction is shown below.

Reaction (i)